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Ilia_Sergeevich [38]
2 years ago
11

Question One:

Mathematics
1 answer:
Jobisdone [24]2 years ago
8 0

Probability that 2 of the 10 chargers will be defective =0.35

Number of ways of selecting 10 chargers from 20 chargers is 20C10

20C10 = 184756

Number of ways of selecting 10 chargers from 20 = 184756

Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2

5C2 = 10

Since 2 defective chargers have been chosen, there remains 8 to choose

Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8

Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435

Probability that 2 of the 10 will be defective =

(10x6435)/184756

Probability that 2 of the 10 will be defective = 64350/184756

Probability that 2 of the 10 chargers will be defective =0.35

Learn more on probability here: brainly.com/question/24756209

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