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Ilia_Sergeevich [38]
3 years ago
11

Question One:

Mathematics
1 answer:
Jobisdone [24]3 years ago
8 0

Probability that 2 of the 10 chargers will be defective =0.35

Number of ways of selecting 10 chargers from 20 chargers is 20C10

20C10 = 184756

Number of ways of selecting 10 chargers from 20 = 184756

Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2

5C2 = 10

Since 2 defective chargers have been chosen, there remains 8 to choose

Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8

Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435

Probability that 2 of the 10 will be defective =

(10x6435)/184756

Probability that 2 of the 10 will be defective = 64350/184756

Probability that 2 of the 10 chargers will be defective =0.35

Learn more on probability here: brainly.com/question/24756209

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Answer:

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Step-by-step explanation:

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A spinner with two equal sectors is spun 5 times.
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Answer:

There are 32 outcomes that are possible

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Julie manages a franchise restaurant and is analyzing the tips left at her location. From corporate informational material, she
Korolek [52]

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$6.66 and $7.04

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Yu and Elena each bought between 7 and 9 yards of ribbon. Yu
Mumz [18]

Given: Yu, Nailah, and Elena each bought between 7 and 9 yards of ribbon  Yu bought 3 pieces of ribbon. Nailah bought 5 pieces of ribbon. Elena bought 6 pieces of ribbon.

To find: Who can buy which ribbon

Solution:

Ribbon Sizes

1 2/3 = 5/3  yard

4/5  yard

3 1/2  = 7/2 Yard

Yu, Nailah, and Elena each bought between 7 and 9 yards of ribbon

Yu bought 3 pieces of ribbon

=> 3 * 5/3  = 5

  3 * 4/5  = 2.4

  3 * 7/2   = 10.5

Nailah  bought 5 pieces of ribbon

=> 5 * 5/3  = 8.33

   5 * 4/5  =  4

   5 * 7 /2   = 17.5

Elena bought 6 pieces of ribbon

=> 6 * 5/3  = 10

  6 * 4/5  = 4.8

  6 * 7 /2   = 21

Only value between 7 & 9 is 5 * 5/3  = 8.33

hence Nailah only can buy 1 2/3 = 5/3  yard ribbon

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6 0
2 years ago
I need help understanding this and help with the problems...
Pavel [41]

1. 15+37=?

  • 15=10+5 (given on the diagram)
  • 37=30+7 (given on the diagram)
  • add digits to digits 5+7=12=10+2
  • add tens to tens 10+30+10=50
  • add tens and digits 50+2=52.

2. 22+49=?

  • 22=20+2 (given on the diagram)
  • 49=40+9 (given on the diagram)
  • add digits to digits 2+9=11=10+1
  • add tens to tens 20+40+10=70
  • add tens and digits 70+1=71.

3. 38+26=?

  • 38=30+8 (given on the diagram)
  • 26=20+6 (given on the diagram)
  • add digits to digits 8+6=14=10+4
  • add tens to tens 30+20+10=60
  • add tens and digits 60+4=64.

Answer: 1) 52; 2) 71; 3) 64.

7 0
3 years ago
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