What is the slope of the line that passes through (-6,13) and (8,-29)

What are the extremes of the following proportion? 3⁄15 = 12⁄60

pashok25 [27]

Answer:

3 and 60

Step-by-step explanation:

For the given proportions, $\frac { 3 } { 15 } = \frac { 12 } { 60 }$ , 3 and 60 are the extremes while 12 and 15 are the means.

To understand this, we can take a look at an example.

Suppose two ratios a:b and c:d are in proportion.Then it can be expressed as :

$ab=cd$

Here, a and d are the extreme ends and b and c are the means.

6 0

3 years ago

Algebra: E=1/2mv^2+mgh Solve for V

Fantom [35]

Answer:

v= $\sqrt{x} 2E-gh$

Step-by-step explanation:

8 0

3 years ago

What value of x makes the equation true?

gtnhenbr [62]

Answer:

$1.4x + 2.6x = - 16 \\ 4x = - 16 \\ x = \frac{ - 16}{4} \\ x = - 4 \\ thank \: you$

4 0

3 years ago

Read 2 more answers

If we assume the population of Grand Rapids is growing at a rate of approximately 4% per decade, we can model the population fun

saw5 [17]

Answer:

The average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ] are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

Step-by-step explanation:

The given function is

$P(t)=181843(1.04)^{(\frac{t}{10})}$

where, P(t) is population after t years.

At t=5,

$P(5)=181843(1.04)^{(\frac{5}{10})}=185444.20$

At t=6,

$P(6)=181843(1.04)^{(\frac{6}{10})}=186172.95$

At t=7,

$P(7)=181843(1.04)^{(\frac{7}{10})}=186904.57$

At t=8,

$P(8)=181843(1.04)^{(\frac{8}{10})}=187639.06$

At t=9,

$P(9)=181843(1.04)^{(\frac{9}{10})}=188376.44$

At t=10,

$P(10)=181843(1.04)^{(\frac{10}{10})}=189116.72$

The rate of change of P(t) on the interval $[x_1,x_2]$ is

$m=\frac{P(x_2)-P(x_1)}{x_2-x_1}$

Using the above formula, the average rate of change of the population on the intervals [ 5 , 10 ] is

$m=\frac{P(10)-P(5)}{10-5}=\frac{189116.72-185444.20}{5}=734.504$

The average rate of change of the population on the intervals [ 5 , 9 ] is

$m=\frac{P(9)-P(5)}{9-5}=\frac{188376.44-185444.20}{4}=733.06$

The average rate of change of the population on the intervals [ 5 , 8 ] is

$m=\frac{P(8)-P(5)}{8-5}=\frac{187639.06-185444.20}{3}=731.62$

The average rate of change of the population on the intervals [ 5 , 7 ] is

$m=\frac{P(7)-P(5)}{7-5}=\frac{186904.57-185444.20}{2}=730.185$

The average rate of change of the population on the intervals [ 5 , 6 ] is

$m=\frac{P(6)-P(5)}{6-5}=\frac{186172.95-185444.20}{1}=728.75$

Therefore the average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ] are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

7 0

4 years ago

In an average of 65 minutes if a train stops at three stations for two minutes each and the distance is 115 miles between stops

larisa86 [58]

Answer:

117mph

Step-by-step explanation:

Given that

Total number of stations= 3

Total average time of journey of train = 65

total stop time at three stations = 3×2 =6 min

Total distance between stops = 115 miles

as we can see

Total time train was travelling = 65- 6 =59 min

so, average speed of train can be calculated as:

Average Speed = $\frac{Distance -travelled-between -stations}{Total-time-the-train-travelled}$

Average Speed = $\frac{115}{59} =1.95 miles/minute$

To convert this speed into miles per hour (mph) multiply the above speed by 60

Average speed = 60×1.95 =117 mph

So the average speed of train is 117mph.

3 0

3 years ago