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Svetllana [295]

3 years ago

12

Algebra: E=1/2mv^2+mgh Solve for V

1 answer:

Fantom [35]3 years ago

8 0

Answer:

v= $\sqrt{x} 2E-gh$

Step-by-step explanation:

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A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 10.4

vlabodo [156]

Answer:

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

Step-by-step explanation:

Bernoulli's equation,

$P_1+\frac12 \rho v^2_1+\rho g h_1= P_2+\frac12 \rho v^2_2+\rho g h_2$

P₁ = P₂= atmospheric presser

$\rho$ = density

$\frac12 \rho v^2_1+\rho g h_1= \frac12 \rho v^2_2+\rho g h_2$ [since P₁ = P₂]

$\Rightarrow\rho (\frac12 v^2_1+ g h_1)= \rho(\frac12 v^2_2+ g h_2)$

$\Rightarrow\frac12 v^2_1+ g h_1= \frac12 v^2_2+ g h_2$

$\Rightarrow\frac12 v^2_2-\frac12 v^2_1=g h_1- g h_2$

$\Rightarrow v^2_2- v^2_1=2g h$ [ $h_1-h_2=h$ ]

Here $v_1\approx 0$

$\Rightarrow v^2_2=2g h$

$\therefore v_2=\sqrt {2gh$

Here g= 9.8 m/s² , h = 10.4 m

The velocity of water that leaves from the hole $v_2$ = $\sqrt {2\times 9.8\times 10.4}$ m/s

=14.28 m/s.

Given, the rate of flow from the leak is $2.53\times 10^{-3}$ $m^3/min$

$=\frac{2.53\times 10^{-3}}{60}$ $m^3/s$

Let the diameter of the hole be d.

Then the cross section area of the hole is $=\pi (\frac d2)^2$

We know that,

The rate of flow = Cross section area × speed

$\Rightarrow \frac{2.53\times 10^{-3}}{60} =\pi (\frac d2)^2\times 14.28$

$\Rightarrow (\frac d2)^2=\frac{2.53\times 10^{-3}}{60\times 14.28\times \pi}$

$\Rightarrow d= 1.94 \times 10^{-3}$

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

4 0

4 years ago

Given sinx=725 and cosx=2425 .<br><br><br><br> What is ratio for tanx ?

viva [34]

We have the fomular:

$tan(x)= \frac{sin(x)}{cos(x)}$

So try inserting your values and you should get the result.

7 0

4 years ago

Read 2 more answers

)) Find the slope of the line that passes through (10, 1) and (1, 3).

irinina [24]

Answer:

Slope (m)

-0.2222

m = 2 / -9 = -0.222

Step-by-step explanation:

6 0

3 years ago

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The radius of a sphere is 6 units

lesantik [10]

Answer:

288 pi or 904.22

Step-by-step explanation:

(4/3) × pi × r³

(4/3) × pi × 6³

288pi or

288 × 3.14 = 904.32 units³

7 0

3 years ago

Can someone help me with this please?

Diano4ka-milaya [45]

Answer:

your awnser would be. 1/4

5 0

3 years ago

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