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3 years ago

I need help with all of these I don’t get it

Mathematics

1 answer:

pochemuha3 years ago

8 0

The first question each friend gets 1/8 of the whole pizza
for half of the pizza each friend gets 1/4 so that times 2 equals 1/8

The second question one person gets 1/15 of the brownie pan
1/5 times 3 equals 1/15

The third question 1/3 cup one serving 1 cup three servings three times six equals 18 servings

The fourth question 1/5 cup one muffin one cup 5 muffins five times nine equals forty-five muffins

Hope this helps

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g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for <em>h: </em>

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

$\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r} \end{aligned}$

Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0

3 years ago

What is the relationship between the center of any circle and the point that lie on the circle?

Arlecino [84]

The distance between the center and any point on the circle is the radius. That's likely what your book or teacher is asking for.

Note: double the radius and you get the diameter

7 0

3 years ago

Read 2 more answers

What is the LCD of 1/3 and 1/4

deff fn [24]

I think it’s 12

1/3 = 4/12
1/4 = 3/12

Hope it’s correct

7 0

3 years ago

Given four functions, which one will have the highest y-intercept? f(x) g(x) h(x) j(x) Blake is tracking his savings account wit

denis23 [38]

Answer is j(x) everything else i think is incorrect.

4 0

3 years ago

Find the midpoint of the line segment joining the points P1 and P2. P1 = (x, 8); P2 = (0, 9)

ipn [44]

Answer:

(x/2 , 17/2)

Step-by-step explanation:

To find a midpoint, you average the x's and average the y's. Average them by adding the x-coordinates and divide by 2. Same with the y's.

The x's are x for P1 and 0 for P2.

x+0 / 2

=x/2

This will be the x-coordinate of the midpoint. Then for the y, use 8 and 9, the y's.

8+9 / 2

= 17/2

This will be the y-coordinate of the midpoint.

The midpoint is:

(x/2 , 17/2)

You could also divide 17/2 and get 8.5 then the midpoint would be:

(x/2 , 8.5)

5 0

2 years ago