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Ksivusya [100]
3 years ago
13

SOMEONE Help ASAP ILL give 30 point and the thing

Mathematics
1 answer:
Gwar [14]3 years ago
8 0

Answer:

please indicate what p, i, or m means. It does not specify so I will assume that p is proper. I is improper fraction and m is mixed number. 6. P, m, and i. 7 is m, and i

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PLEASEEE HELPPPP ASAPPPP
stellarik [79]

\cos 27^{\circ} = \dfrac{KL}x\\\\\implies \cos 27^{\circ} = \dfrac{6.3}x\\\\\implies x = \dfrac{6.3}{\cos 27^{\circ}}=7.1~ \text{units.}

6 0
2 years ago
Dylan made $45,765 and Orlando made $34,715. Both boys worked for 6 months. How much more money did Dylan earn than Orlando per
Ymorist [56]

Answer:

$425

Step-by-step explanation:

45,765 divided by 26 equals 1,760.192307692308

34,715 divided by 26 equals 1,335.192307692308

1,760.192307692308-1,335.192307692308=425

5 0
3 years ago
Tom planted 1/2 of an 8-ft by 9-ft garden with vegetables. He planted tomatoes in 1/3 of the vegetable garden and corn in the re
ser-zykov [4K]

Answer:

Corn was planted in 24 sq.ft. of the vegetable garden.

Step-by-step explanation:

Length of garden = 9 ft

width of garden = 8 ft

Hence we will first find the total area of garden.

Total area of garden = length × width = 8 \times 9 = 72ft^2

He planted 1/2 of the garden with vegetables.

Hence.

Area of Vegetables garden = \frac{1}{2}\times \textrm{Total Area of Garden} = \frac{1}{2}\times 72 = 36ft^2

He planted tomatoes in 1/3 of the vegetable garden and corn in the rest

Area in which tomatoes was planted = \frac{1}{3}\times \textrm{Area of Vegetables Garden} = \frac{1}{3}\times 36 = 12ft^2

Hence Area in which corn were planted = Area of Vegetables garden - Area in which tomatoes was planted = 36ft^2-12ft^2=24ft^2

Hence Area of vegetable garden in which corn was planted is 24 sq.ft.

7 0
3 years ago
Please help if u see this
jek_recluse [69]
<h3>Answer: Choice D</h3>

(f \circ g)(x) = x+12

Domain = [-3, infinity)

==================================================

Work Shown:

f(x) = x^2 + 9\\\\f(g(x)) = (g(x))^2 + 9\\\\f(g(x)) = (\sqrt{x+3})^2 + 9\\\\f(g(x)) = x+3 + 9\\\\f(g(x)) = x+12\\\\(f \circ g)(x) = x+12\\\\

In step 2, we replaced every x with g(x)

In step 3, we plugged in g(x) = sqrt(x+3)

The domain of g(x) is [-3, infinity), so this is the domain of (f \circ g)(x) as well since the composite function depends entirely on g(x). Put another way: the input of f(x) depends on the output of g(x), so that's why the domains match up.

7 0
3 years ago
What is the product of 1 and 1 3rd and 7/10
Dmitrij [34]
The correct answer is 14/15. To answer this problem, it would help to change the mixed number into an improper fraction.

1 1/3
4/3   Multiply 3 by 1, and then add 1 and put 4 over 3.

4/3 x 7/10   Now, multiply both numbers by each other. Since we're multiplying, we don't need to find a least common denominator.
28/30   4 x 7 = 28; 3 x 10 = 30
14/15   Since 28 and 30 are divisible by 2, we need to simplify the answer.

The correct answer is 14/15.

Hope this helps!
3 0
3 years ago
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