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____ [38]
3 years ago
15

Nelson Middle School raised $19,950 on ticket sales for its carnival fundraiser last year at $15 per ticket. If the school sells

the same number of tickets this year but charges $20 per ticket, how much money will the school make?
A $26,600
B $21,600
C $30,600
D $20,600
Mathematics
2 answers:
Nina [5.8K]3 years ago
8 0

Answer:

C 30600 dollars hope it helps

musickatia [10]3 years ago
3 0

Answer:

$26,600

Step-by-step explanation:

19,950/15 to get the number of tickets sold last year.

1330 tickets

1330*20=

$26,600 if they sell the same number of tickets.

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Heeeeeelp! I’m literally so behind
olchik [2.2K]

Answer:

That would be 9 my good sir ( or ma'am )

Step-by-step explanation:

basicly round the 61 so that there would not be a remainder and divide 54 by 6 you will get 9, so therefore the same case is for 540 by 60.

Have a nice day

7 0
3 years ago
Is (-7/8) with exponent 12, positive or negative?
bulgar [2K]

Answer:

There is a 100% possibility that it can be Positive

Step-by-step explanation:

Because it will actually equal 0.201417238

You don't believe me?

Then use a calculator, and if you still don't believe me, the truth is that you're wrong!

But hope this helps

3 0
3 years ago
Read 2 more answers
The resistance of a strain gauge is normally distributed with a mean of 100 ohms and a standard deviation of 0.3 ohms. To meet t
zloy xaker [14]

Answer: 0.6827

Step-by-step explanation:

Given : The resistance of a strain gauge is normally distributed .

Population mean : \mu=100

Standard deviation : \sigma=0.3

Let x be the random variable that represents the resistance of a strain gauge is normally distributed .

z-score : z=\dfrac{x-\mu}{\sigma}

To meet the specification, the resistance must be within the range 100±0.7 ohms i.e. (99.3,100.7).

For x = 100.7

z=\dfrac{100.7-100}{0.7}=1

For x = 99.3

z=\dfrac{99.3-100}{0.7}=-1

By using the standard normal distribution table, The proportion of gauges is acceptable is given by:-

P(99.3

Hence, the proportion of gauges is acceptable=0.6827

4 0
3 years ago
(-1/2)^3 divided by (1/4)^5
lesya [120]

Answer:

-128

Step-by-step explanation:

4 0
3 years ago
A data scientist studying a manufacturing process classifies each item produced by the process as either Poor, Acceptable, or Ex
Genrish500 [490]

Answer:

0.214 ; 0.064 ; 0.3859 ; 0.9966 ; 0.135

Step-by-step explanation:

Given the distribution :

Poor ___ Acceptable ____ Excellent

0.25 _____ 0.6 _________ 0.15

The data scientist receives three items produced by the manufacturing process.

Find the chance that:

a. all of items are Acceptable

0.6 * 0.6 * 0.6 = 0.6^3 = 0.214

b. none of the items is Acceptable

P(not acceptable) = 1 - p(acceptable) = 1 - 0.6 = 0.4

0.4 * 0.4 * 0.4 = 0.4^3 = 0.064

c. at least one of the items is Excellent

P(atleast one) = 1 - P(none)

P(not excellent) = 1 - 0.15 = 0.85

P(none is excellent) = 0.85^3 = 0.614125

Hence,

P(atleast one is excellent) = 1 - 0.614125 = 0.3859

d. not all of the items are Excellent

P(not all) = 1 - p(All)

P(all excellent) = 0.15^3 = 0.003375

P(not all are excellent) = 1 - 0.003375 = 0.9966

e. there is one item of each class:

P(poor) * p(acceptable) * p(excellent) * (number of classes)!

0.25 * 0.6 * 0.15 * 3!

= 0.135

3 0
3 years ago
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