Answer:
2< AC<8
Step-by-step explanation:
For a triangle to exits sum of two sides must always be greater than the the third side
⇒ AC< AB+ BC =5+3=8 in
⇒AC<8 in
Also, the difference of the two sides must be smaller than the length of third side
⇒ AC> | AB-BC| = |5-3| =2
AC> 2 in
therefore, we can say 2< AC<8. Hence, AC can takes 3,4,5,6 values
Answer:
i think it A
Step-by-step explanation:
Answer:
the answer is none of those it is 4/13
No.
Since w = 8, you must replace the variable with the number associated to it.
So, it would be 5 + 8 = 58
5 + 8 is not equal to 58, it is equal to 13.
If you wanted to find out what w was, simply subtract 5 on both sides.
w = 58 - 5
6x-2y=2
-3x+4y=5
2(-3x)+2(4y)=2(5)
-6x+8y=10
6x-2y=2
-6x+8y=10
6y=12
y=2
6x-2(2)=2
6x-4=2
6x=6
x=1
y=2 and x=1
