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hjlf
3 years ago
7

Numbers like 10, 100, 1,000, and so on are called?

Mathematics
1 answer:
mylen [45]3 years ago
3 0
Numbers starting with a 1 and followed by only 0s (such 10, 100, 1,000,10,000, and so forth) are called powers of ten, and they're easy to represent as "exponents". Powers of ten are the result of multiplying 10 times itself any number of times.
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Which of the following is most likely the next step in the series
Anna35 [415]

Answer:

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8 0
2 years ago
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In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i
PilotLPTM [1.2K]
Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,


was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

\bf \displaystyle \int -32\cdot dt\implies -32t+C
\\\\\\
\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}
\\\\\\
-32(0)+C=0\implies C=0\implies \boxed{v(t)=-32t}
\\\\\\
\textit{now to get the positional s(t)}
\\\\\\
\displaystyle \int -32t\cdot dt\implies -16t^2+C
\\\\\\
\textit{the initial \underline{position} was 400ft away at 0secs}
\\\\\\
-16(0)^2+C=400\implies C=400\implies \boxed{s(t)=-16t^2+400}

when will it reach the ground level? let's set s(t) = 0

\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2
\\\\\\
25=t^2\implies \boxed{5=t}


part B)  check the picture below

5 0
3 years ago
In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 9
creativ13 [48]
So...we can write eqn as

40x = 50(x-1)
so. -10x=-50
so. x=5

therefore .... the distance of 40 lb will be 5 ft ...answer !!!
4 0
3 years ago
Read 2 more answers
Please help me with this question
kiruha [24]

Answer:

First Row: Given

Second Row: Definition of Regular Polygon

Third Row: Definition of Congruence In Terms of Rigid Motion

Fourth Row: Definition of Regular Polygon

Fifth Row: SAS Triangle Congruence Theorem

Sixth Row: CPCTC

Step-by-step explanation:

This is a basic proof in order to prove that verticals of a polygon are congruent. This should be the right answer since it's the only thing that makes sense to me. I really hope this helps you and thanks for being patient! I've been doing geometry and we have to prove everything we claim in a proof just like this one. However, there was one I kind of guessed on (the third row), but I think it should be correct! I saw from the photo that you have a check answer on the bottom of your screen. Just check the answers that I have for you now and if something is wrong, then we can continue talking about it! Hope this helps!! :)

3 0
3 years ago
Is −2π rational or irational?
Maru [420]
Irrational.
Rational means that you can write it as a fraction, you cannot express pi as a fraction therefore it’s not rational
4 0
2 years ago
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