The a is idshdvsvehdhdbdhdhggansnsbfsbshd
Considering that the square root of 9 is of 81 and of 10 is of 100, we have that the expression that has a value between 9 and 10 is given by:
B.) √89
E.) ![\sqrt[3]{750}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B750%7D)
F.) ![\sqrt[3]{999}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B999%7D)
<h3>How the square root of a number is used to solve this question?</h3>
We suppose numbers n and m, with square roots given, respectively, by n² and m².
Then, the square roots of all numbers between n² and m² have values between n and m.
In this problem, the square roots are given by:
Hence, the square root of all values between 82 and 99 are values between 9 and 10, thus option B is correct.
As for the cubic root, we apply the same logic and have that:
Hence options E and F are also correct, as the values between 730 and 999 have cubic roots between 9 and 10.
More can be learned about the value of a expression at brainly.com/question/25537936
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We can form two ratios to help us solve this:
(2x+6):10 = (x+6):8
(2x+6) (x+6)
--------- = --------
10 8
Cross multiply:
8(2x+6) = 10(x+6)
Foil:
16x + 48 = 10x + 60
Move like variables to the same side:
16x - 10x = 60 - 48
6x = 12
x = 2
Line AE = 2x+6
Plug 2 for x into the equation: 2(2) + 6 = 10
Hope this helps, and May the Force Be With You!
-Jabba