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3 years ago

How do I write 3x3x3x3 in exponential form

Mathematics

1 answer:

yarga [219]3 years ago

6 0

Answer:

3 with the exponent of four.

Step-by-step explanation:

You would count the number of of three's. Since there are four three's, then you would write the 4 right by the three on the top right hand corner.

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Gena has 28 trading cards sam has 91 and tiffany has 49 trading cards. Use the GCF and the distributive property to find the tot

topjm [15]

Wouldn't you just add up the cards so it'd be 28 + 91 + 49 = 168 trading cards in total.

4 0

3 years ago

Let f(x)=2x^2+7x-5 and g(x)=-8x^2-3x+5 what is g(x)+f(x)

ser-zykov [4K]

F(x) = 2x² + 7x - 5
g(x) = -8x² - 3x + 5
g(x) + f(x) = -8x² - 3x + 5 + 2x² + 7x - 5 = - 6x² + 4x

Answer: -6x² + 4x

4 0

4 years ago

Read 2 more answers

Use the interactive tool to find the difference. (–4) – 6

elena55 [62]

(−4) − 6

Remove Parenthesis

-4 - 6

Subtract the numbers:

- 4 - 6 = 10

= −4 −6

= −4 + −6

Answer = −10

Hope that helps!!! : )

6 0

3 years ago

Read 2 more answers

Which expression is equivalent to 6(2y - 5)?

Cloud [144]

Answer:

12y-30

Step-by-step explanation:

7 0

3 years ago

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Find the error & find the correct answer 2In(x)=In(3x)-[In(9)-2In(3)] In(x^2)=In(3x)-[In(9)-In(9)] In(x^2)=In(3x)-0 In(x^2)=

Art [367]

Answer:

Error: $lnx^2=ln 3x$ not $ln\frac{3x}{0}$

Solution:x=0 and 3

Step-by-step explanation:

We have to find the error and correct answer

Given: $2ln x=ln(3x)-[ln9-2ln(3)]$

$lnx^2=ln(3x)-[ln9-ln3^2]$

Using the formula

$alog b=logb^a$

$lnx^2=ln(3x)-[ln9-ln9]$

$lnx^2=ln(3x)-0$

$lnx^2=ln(3x)$

$x^2=3x$

$x^2-3x=0$

$x(x-3)=0$

Therefore, x=0 and x=3

But last step in the given solution

$lnx^2=ln\frac{3x}{0}=\infty$

It is wrong this property is used when

$log m-log n$ then

$log\frac{m}{n}$

Hence, the student wrote $lnx^2=ln\frac{3x}{0}$ instead of $lnx^2=ln3x$ and solution is given by

x=0 and x=3

4 0

4 years ago