All categories

3 years ago

PLEASE SOLVE THIS PROBLEM

Mathematics

1 answer:

schepotkina [342]3 years ago

7 0

Answer:

18) Area= 5*5/2=25/2=12.5 unit ^2

19) Area=AB^2V3/4=8a^2*V3/4=2V3a^2

Step-by-step explanation:

18. A(-3,0)

B(1,-3)

C(4,1)

AB=V(-3-1)^2+(0+3)^2=V16+9=V25=5

AC=V(-3-4)^2+(0-1)^2=V49+1=V50=5V2

BC=V(1-4)^2+(-3-1)^2=V9+16=V25=5

so AB=BC=5

and AC^2=AB^2+BC^2

so trg ABC is an isosceles right angle triangle (<B=90)

Area= 5*5/2=25/2=12.5 unit ^2

19. A(a,a)

B(-a,-a)

C(-V3a, V3a)

AB=V(a+a)^2+(a+a)^2=V4a^2+4a^2=V8a^2

AC=V(a+V3a)^2+(a-V3)^2=Va^2+2a^2V3+3a^2+a^2-2a^2V3+3a^2=V8a^2

BC=V(-a+V3a)^2+(-a-V3a)^2=V8a^2

so AB=AC=BC

Area=AB^2V3/4=8a^2*V3/4=2V3a^2

You might be interested in

Can someone help me with this? its solving systems by substitution

yKpoI14uk [10]

Answer: x = 1 and y = 2

Given:
y = -3x + 5
5x - 4y = -3

Since we are given y, let’s sub it in the second equation.

5x - 4(-3x + 5) = -3
5x + 12x - 20 = -3
17x = 17
x = 1

After finding x, we can now find y.

5(1) - 4y = -3
-4y = -8
y = 2

Checking:

y = -3x + 5
2 = -3(1) + 5
2 = 2

5x - 4y = -3
5(1) - 4(2) = -3
-3 = -3

8 0

2 years ago

Find the slope between the following 2 coordinate points. (-3,6) and (-1,-8)

padilas [110]

The slope formula is y2-y1 divided by x2- x1 so -8-6=-14 and -1+3=2
-14/2 =-7

3 0

3 years ago

Read 2 more answers

Can someone please help me i will give free 50 points

Grace [21]

Would it be 11 and 12?

6 0

2 years ago

Read 2 more answers

The decreasing population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p=−0.

n200080 [17]

By solving a quadratic equation, it can be verified that

The owl population will disappear after 329.12 years

What is a quadratic equation?

At first it is important to know about equation

Equation shows the equality between two algebraic expressions by connecting the two algebraic expressions by an equal to sign.

A two degree equation is known as quadratic equation.

Here, a quadratic equation needs to be solved

The decreasing population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p= $-0. 4t^2+128t+1,200$

For population to disappear, p =0

$-0. 4t^2+128t+1,200 = 0\\0.4t^2 -128t - 1200 = 0\\4t^2 - 1280t - 12000 = 0\\4(t^2 - 320 t - 3000) = 0\\t^2 - 320t -3000 = 0\\t = \frac{-(-320)\pm \sqrt{(-320)^2 - 4 \times 1 \times (-3000)}}{2 \times 1}\\t = \frac{320 \pm 338.23}{2}\\t = \frac{320 + 338.23}{2} \ or \ t = \frac{320 - 338.23}{2}\\t = 329.115 \ or \ t = -9.115$

But t = -9.115 is not possible as time cannot be negative

So, the owl population will disappear after 329.12 years

To learn more about quadratic equation, refer to the link-

brainly.com/question/1214333

#SPJ4

7 0

1 year ago

If you had an individual who was gifted and talented in math, and well above the rest of your class, how might you use different

irakobra [83]

Answer:

See explanation below.

Step-by-step explanation:

Having students in the classroom who are at different levels of knowledge, interest, and ability can be managed by differentiated instruction. This method is a way of thinking that provides a framework where the instructor can set students with learning tasks that are at levels appropriate with the abilities and interests of each student. Each student can have a different type of class and different type of instruction with the differentiated instruction way of thinking.

A gifted and talented student might be assigned a higher math course, perhaps based on a math assessment for advanced placement. Then students that need to stay on the typical high school path of Algebra I, Geometry, Algebra II, and Trigonometry can do that.

Gifted students might take an alternate path with honors classes or trajectories involving Pre-Calculus or advanced placement Calculus, for example. In some instances, universities have allowed High School students to obtain college credit for some courses taken during High School.

Hope this helps! Have an Awesome Day!! :-)

6 0

3 years ago

PLEASE SOLVE THIS PROBLEM ​

PLEASE SOLVE THIS PROBLEM