Isolate for each variable.
1. z= 6 - 10
z= -4
2. y= 48/8
y=6
3. q= 1+12
q= 13
4. 18 x 2= a
36= a
5. r= 7 x 3
r= 21
I think you can try the rest :)
Answer:
This quadratic equation has 2 solutions.
Step-by-step explanation:
I assume the '?' in your question is meant to be power 2 (²), or else it would not be a quadratic equation. You could write it using the superscript version of 2.
We can solve this equation by expressing it in the form: ax² + bx + c
x² + 9x= -8
x² + 9x + 8 = 0
Now if you know the discriminant, you can simply plug in your values of a, b, and c to see how many solutions there are.
In this case, you would not need the discriminant as there are whole-number factors and hence this can simply be factorised.
x² + 9x + 8 = 0
(x + 8)(x + 1) = 0
For this equation to be true (= 0), x can equal -8 OR -1.
Hence, this quadratic equation has 2 solutions.
<u><em>Answer:</em></u>
<u><em>x < -7</em></u>
<u><em>Step-by-step explanation:</em></u>
<em><u>Divide both sides by 3</u></em>
<em><u>simplify</u></em>
<em><u>add 4 to both sides</u></em>
1/3y + 28 = -5
Subtract 28 from both sides:
1/3y = -33
Multiply both sides by 3:
y = -99
The answer is E) NOTA
