Answer:
P(A∩B) = 0.522
Step-by-step explanation:
Let's call A the event that a puppy is adopted and B the probability that a puppy live 7 or more years
So, the probability P(A∩B) that a randomly selected puppy in the shelter will get adopted and live 7 or more years is:
P(A∩B) = P(A)*P(B/A)
Because A and B are not independents.
Then, the probability P(A) that a puppy is adopted is 58% and the probability P(B/A) that a puppy live 7 or more years given that the puppy is adopted is 90%.
Finally, replacing the values, we get:
P(A∩B) = 0.58*0.9 = 0.522
It means that the 52.2% of the puppies are adopted and live 7 or more years.
36 questions-----3 minutes
x questiones-----1 minutes
x=(1*36)/3
x=36/3
x=12 questions
B.
First expression
=> 3 x 3 x 3 x 3 x 3 – In this expression, we multiplied 3 5 times and the product is 243
Second expression
=> 3 ^ 5 , in where ^ read as raised to the power. , the product is also 243
Third expression
=> 3^2 x 3 ^3
=> (3 x 3) x (3 x 3 x 3)
=> 9 x 27, the product is also equals to 243.
