given that a race car driver tested his car for time from 0 to 60 mph, and in 20 tests obtained an average of 4.85 seconds with a standard deviation of 1.47 seconds.

Sample size n = 20

since population standard deviation is not known, we can use t critical value for finding out the confidence interval

df=19

t critical = 2.045

Margin of error = $2.045*\frac{s}{\sqrt{n} } \\=2.045*\frac{1.47}{\sqrt{20} } \\=0.6722$

conidence interval = Mean±Margin of error

= $(4.85-0.6722, 4.85+0.6722)\\= (4.1778, 5.5222)$

The given confidence interval is (4.52, 5.18)

Hence the statement is false.

5 0

3 years ago

Find the equation of the line through point (−5,5) and perpendicular to y=59x−4

VARVARA [1.3K]

Answer:

Step-by-step explanation:

5 0

1 year ago

A group of friends go to a local fair. Jason spends $3.75. My has spent three times as much as Jason. Tia spend $5.25 more than

lisov135 [29]

Answer:

$16.50

Step-by-step explanation:

If Jason spends $3.75 and Maya spends three times that amount, Maya spends 3.75(3) or $11.25. If Tia spends $5.25 more than Maya, Tia spends 11.25 + 5.25 or $16.50.

4 0

3 years ago

Help solving this math

Anna [14]

-3.6
Explaination: it goes through the 6 and -3 points in the slope.

4 0

2 years ago

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