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rosijanka [135]
3 years ago
12

-3s = -24 what does S equal

Mathematics
2 answers:
qaws [65]3 years ago
8 0
-3s=-24 to find s you will divide both sides by -3
S=8
raketka [301]3 years ago
7 0
-3s = -24

-3 x what will equal to -24

We know that 3 x 8 = 24

So -3 x 8 = -24

Always remember positive x negative = negative

Negative x negative = positive

Hope this helps have an awesome day... ;)
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Please help radical expression dividing
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\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad 
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63=3\cdot 3\cdot 7\\
6=2\cdot 3
\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}
\\\\\\
\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}

\bf \textit{now, rationalizing the denominator}\\\\
\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}
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and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.
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