the answer is 4.2 and i check if the answer is correct
and it was correct
Answer: 0.9738
Step-by-step explanation:
This is solved by the probability distribution formula for random variables where probability of determining random variable X is given by
P(X=r) = nCr * p^r * q^n-r
Where n = number of sample = 6
p = probability of success = 0.545
q = 1-p = 0.455
r = possible outcome from number of sample.
If 6 random births are chosen, Probability that at least 1 of them is a girl = 1 -[probability that none of them is a girl] = 1 - [probability that all 6 kids are boys]
Probability that all 6 kids are boys = 6C6 * 0.545^6 * 0.455^0 = 0.0262
Probability that at least one is a girl = 1 - 0.0262 = 0.9738.
Answer: let
Total number of those who took part in the survey (T)=3200
Those who were satisfied (t)=960
Percentage of those who were satisfied (S)=(t/T)*100
S=(960/3200)*100
S=30%
Therefore only 30% were satisfied
Step-by-step explanation: