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Travka [436]
3 years ago
11

1) A pre-engineering student builds 1

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
6 0

1) Assuming that 1 month is 30 days. We would take 30 (# of days in the month) divided by 4, which would be 7.5. So every 7.5 days ( or 1/4 of a month) she will build 1 1/2 simple machines. so 1 1/2 times 4 equals 6. She will build 6 simple machines each month.

3) D. 6 miles, you would take 60 divided by 6 which is 10, divided by 3/5 which is 6.

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You order some food through Uber Eats, which totals $16.00. You plan on tipping the delivery person 18% for bringing your food.
Korvikt [17]

Answer:

18.88

Step-by-step explanation:

16 x 1.18=18.88

7 0
3 years ago
HELP PLZ Javier and his study group designed a word problem, equation, table, and graph that were all supposed to represent the
Ganezh [65]

Answer:

Graph

Step-by-step explanation:

The graph swapped the y and x axis values.

8 0
3 years ago
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Will mark brainliest help!
kakasveta [241]

Answer:

52.5

Step-by-step explanation:

Since ED ≈ AD, ∆AED is a isosceles triangle where <EAD and <AED has same angle measurement

Now, m<B = 105°, since ABCD is a parallelogram, <B = <D

so, m<ADC = 105° so, m<ADE = 180°-105° = 75°

Now, m<EAD+m<AED+m<ADE = 180°

or, m<AED+m<AED+m<ADE = 180°

or, x+x+75°=180°

or, 2x=180+75°

or, 2x=105°

or, x=52.5°

3 0
2 years ago
Suppose that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to
attashe74 [19]

Answer:

0.9726 = 97.26% approximate probability that X is at most 30

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to be scrapped).

This means that p = 0.11

Random sample of 200 shafts

This means that n = 200

Mean and Standard deviation:

\mu = E(x) = np = 200*0.11 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{200*0.11*0.89} = 4.42

(a) What is the (approximate) probability that X is at most 30

Using continuity correction, this is P(X \leq 30 + 0.5) = P(X \leq 30.5), which is the pvalue of Z when X = 30.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{30.5 - 22}{4.42}

Z = 1.92

Z = 1.92 has a pvalue of 0.9726.

0.9726 = 97.26% approximate probability that X is at most 30

8 0
3 years ago
Please help
galina1969 [7]

Answer:-1.2 Degree Fahrenheit.

Step-by-step explanation:

Since,

The average daily changes,   total changes/number of days

Here,

The total changes = - 16.8° F ( - sign shows the decreasing )

And, the number of days = 14

Hence,

⇒ The average daily rate of change in the high temperature in degrees Fahrenheit is -1.2° F.

6 0
3 years ago
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