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3 years ago

-1.5b = 24 what is the answer to b

2 answers:

4 0

Divide -1.5 with 24 since -1.5 has a variable (b)

Answer: -16 (don't forget to bring over the negative sign; a positive divide/mult. by a negative= a negative answer)

zlopas [31]3 years ago

3 0

-16b is the answer :)

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sofia can paint a house in 10 hours juana can paint the same in 9 hours how long would it take them if they worked together

lubasha [3.4K]

If Sofia and Juana worked together I would take them 1 hour

7 0

3 years ago

For what values of x and y must the figure have in order to be a parallelogram

erma4kov [3.2K]

<u>Given</u>:

Given that the parallelogram with the lengths 5x, 3x + 1, 2y - 5 and y.

We need to determine the values of x and y.

<u>Values of x and y:</u>

We know the property that the opposite sides of a parallelogram are congruent.

Thus, we have;

$5x=2y-5$ ------- (1)

$3x+1=y$ ------- (2)

The value of x and y can be determined using the substitution method.

Substituting equation (2) in equation (1), we have;

$5x=2(3x+1)-5$

$5x=6x+2-5$

$5x=6x-3$

$-x=-3$

$x=3$

Thus, the value of x is 3.

Substituting x = 3 in equation (2), we have;

$3(3)+1=y$

$9+1=y$

$10=y$

Thus, the value of y is 10.

5 0

3 years ago

Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

The probability that both televisions work is: 0.42

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$