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mariarad [96]
2 years ago
12

16. The graph of a system of linear inequalities is

Mathematics
1 answer:
Maru [420]2 years ago
6 0

Answer:

Opt C

Step-by-step explanation:

Unlike Equations, Inequalities system, when graph, are not represented as a line or a curve, instead, they are represented as regions, the regions extend below or above the expression, acorrding to the equality sign.

In this exercise, we only have a graph of two inequalities, the region below the interception is the solution to the system, hence, any point located here satisfies the inequality system.

Point A. is outside the region, in fact, is above the line.

Point B is outside the interception region, is above the line as well.

Point D. is below de line, but, still is outside of the interception region.

Only point here is C, located below the line, inside the region of interception

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pshichka [43]
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In the diagram below AFB is congruent to EFD if EFD = 5x + 6, DFC = 19x - 15, and EFC = 17x + 19, find AFE
yanalaym [24]

The angle m∠AFE is 128 degrees.

<h3>How to find angles?</h3>

∠AFB ≅ ∠EFD

∠EFD = 5x + 6

m∠DFC = (19x - 15)°

m∠EFC = (17x + 19)°

m∠AFE = ?

m∠AFB + m ∠EFD + m∠AFE = 180

Therefore,

5x + 6 + 5x + 6 + m∠AFE = 180

5x + 5x + 6 + 6 + m∠AFE = 180

10x + 12 + m∠AFE = 180

10x + m∠AFE = 180 - 12

10x + m∠AFE  = 168

m∠AFE = 168 - 10x

m∠EFC =  m ∠EFD + m∠DFC

17x + 19 = 5x + 6 + 19x - 15

17x - 5x - 19x = 6 - 15 - 19

-7x = - 28

x = 28 / 7

x = 4

Therefore,

m∠AFE = 168 - 10x

m∠AFE = 168 - 10(4)

m∠AFE = 168 - 40

m∠AFE = 128°

Therefore, the angle m∠AFE = 128°

learn more on angles here: brainly.com/question/13212279

#SPJ1

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