Answer:
0.0174 is the answer you are looking for
The probability that the aircraft is overloaded is 97.98%, which means the pilot should take the action.
In a Normal distribution with mean ц and standard deviation σ, the z-score of a measure x is given by:
Z = X-ц / σ
· It measures how many standard deviations the measure is from the mean.
· After finding Z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
· By the Central Limit Theorem, the sampling distribution of sample means of the size n has standard deviation σ
σ = σ /
σ is standard deviation
n is the sample size.
Given that the mean and the standard deviation of the population is 176.1 lb and 35.4 respectively.
⇒ ц = 176.1 and σ = 35.4
For a sample of 43 passengers, we have
n = 43
σ = 
σ = 5.398
Z = X-ц / σ
Z = 
Z = -2.05 has p- value of 0.9798
The probability that the aircraft is loaded is
1 - p-value of Z
1 - 0.0202 = 0.9798
The probability that the aircraft is overloaded is 97.98%
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Answer:
-9y-2(2-7y)+4 expand the brackets using-2
Step-by-step explanation:
-9y-4+14y+4
arrange the like terms
-9y+14y-4+4
=5y becoz -4+4=0
ans=5y
Answer:
The probability that 75% or more of the women in the sample have been on a diet is 0.037.
Step-by-step explanation:
Let <em>X</em> = number of college women on a diet.
The probability of a woman being on diet is, P (X) = <em>p</em> = 0.70.
The sample of women selected is, <em>n</em> = 267.
The random variable thus follows a Binomial distribution with parameters <em>n</em> = 267 and <em>p</em> = 0.70.
As the sample size is large (n > 30), according to the Central limit theorem the sampling distribution of sample proportions (
) follows a Normal distribution.
The mean of this distribution is:

The standard deviation of this distribution is: 
Compute the probability that 75% or more of the women in the sample have been on a diet as follows:

**Use the <em>z</em>-table for the probability.

Thus, the probability that 75% or more of the women in the sample have been on a diet is 0.037.
2x=3
so substitute y=mx+c
rise/run