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3 years ago

How can you write 6000 in exponents

1 answer:

5 0

The prime factorization of 6000 = 2^4•3•5^3.

The prime factors of 6000 are 2, 3 and 5.

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Parallel / Perpendicular Practice

deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

Neither
║
Neither
⊥
║
Neither
Neither
Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; $m_1 = -\dfrac{1}{m_2}$

1. The given equations are in the slope and intercept form

$\ y = 3 \cdot x + 1$

The slope, m₁ = 3

$y = \dfrac{1}{3} \cdot x + 1$

The slope, m₂ = $\dfrac{1}{3}$

Therefore, the equations are neither parallel or perpendicular

Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

$y = 5 \cdot x -\dfrac{7}{2}$

Therefore, the two equations are parallel

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

$y = 2 -\dfrac{1}{2} \cdot x$

Slope, m₁ = $-\dfrac{1}{2}$

$y = \dfrac{1}{2} \cdot x - 2$

Slope, m₂ = $\dfrac{1}{2}$

The slopes

Therefore, m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

The lines are Neither parallel nor perpendicular

Neither

4. The given equations are;

2·y - x = 2

$y = \dfrac{1}{2} \cdot x +1$

m₁ = $\dfrac{1}{2}$

y = -2·x + 4

m₂ = -2

Therefore;

$m_1 \neq -\dfrac{1}{m_2}$

Therefore, the lines are perpendicular

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, $y = \dfrac{3}{4} \cdot x + 3$

Second equation, $y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}$

Therefore, m₁ = m₂, the lines are parallel

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = $\dfrac{13}{5}$

Therefore, the two equations are neither parallel nor perpendicular

Neither

7. The equations are;

2·x + 6·y = -3

Which gives $y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}$

12·y = 4·x + 20

Which gives

$y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}$

m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

Neither

8. 2·x - 5·y = -3

Which gives; $y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}$

5·x + 27 = 6

$x = -\dfrac{21}{5}$

Therefore, the slopes are not equal, or perpendicular, the correct option is Neither

Learn more here:

brainly.com/question/16732089

6 0

3 years ago

Does this graph show a function? Explain how you know.

LekaFEV [45]

Answer:

Step-by-step explanation:

It may look like it failed but it didn't. Nun of the points duplicate

6 0

2 years ago

Anyways I’m so close! Sleep here I come lol

a_sh-v [17]

Answer:

558

Step-by-step explanation:

930

x 0.40

-------------

372

-930

-----------

558

Hope this helped!

3 0

3 years ago

5. Solve the equation. 8/x+3 = 1/x+1

Helga [31]

Answer:

x = -5/7

Step-by-step explanation:

8 1

---------- = ----------

x+3 x+1

Using cross products

8 (x+1) = 1 (x+3)

Distribute

8x+8 = x+3

Subtract x from each side

8x-x +8 = x-x+3

7x+8 =3

Subtract 8 from each side

7x +8-8 =3-8

7x = -5

Divide each side by 7

7x/7 = -5/7

x = -5/7

4 0

3 years ago

Let g be the function given by g(x)=-3x^2-2x+3 evaluate g(-2)

sashaice [31]

g(x) = -3x² - 2x + 3

g(-2) = -3(-2)² - 2(-2) + 3

g(-2) = -12 + 4 + 3 = -5

8 0

3 years ago