What is the range of the function f(x) = + 6?
2 answers:
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It is given in the question that
Point N(7, 4) is translated 5 units up.
And we have to find the coordinates of its image after this transformation.
Since the point translated up by 5 units, so the x coordinate remains same and we have to add 5 to y coordinate.
So the new coordinate after the transformation is
And that's the required coordinate after the given transformation .
Answer:
d = -1/3, 0
Step-by-step explanation:
Subtract the constant on the left, take the square root, and solve from there.
(6d +1)^2 + 12 = 13 . . . . given
(6d +1)^2 = 1 . . . . . . . . . .subtract 12
6d +1 = ±√1 . . . . . . . . . . take the square root
6d = -1 ±1 . . . . . . . . . . . .subtract 1
d = (-1 ±1)/6 . . . . . . . . . . divide by 6
d = -1/3, 0
_____
Using a graphing calculator, it is often convenient to write the function so the solutions are at x-intercepts. Here, we can do that by subtracting 13 from both sides:
f(x) = (6x+1)^ +12 -13
We want to solve this for f(x)=0. The solutions are -1/3 and 0, as above.
