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ch4aika [34]
3 years ago
9

6 of 25

Mathematics
2 answers:
grin007 [14]3 years ago
6 0
$9.513 per meal. hope this helps :)
olasank [31]3 years ago
3 0
9.5139 because you could divide 599.38 by 63 to get 9.5139
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What is equivalent to 40n2−31n+6 ?
bogdanovich [222]

Answer:(8n-3) (5n-2)Step-by-step explanation:

3 0
3 years ago
Find the numbers b such that the average value of f(x) = 7 + 10x − 9x2 on the interval [0, b] is equal to 8.
barxatty [35]

Answer:

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx

If f(x) = 7 +10\cdot x - 9\cdot x^{2}, a = 0, b = b and \bar f = 8, then:

\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8

\frac{7}{b}\int\limits^b_0 \, dx  + \frac{10}{b}  \int\limits^b_0 {x}\, dx - \frac{9}{b}  \int\limits^b_0 {x^{2}}\, dx = 8

\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8

7 + 5\cdot b - 3\cdot b^{2} = 8

3\cdot b^{2}-5\cdot b +1 = 0

The roots of this polynomial are determined by the Quadratic Formula:

b_{1} \approx 1.434 and b_{2} \approx 0.232.

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

7 0
3 years ago
What is the x- intercept of y+ 12 =3 (x-9)?
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Answer:

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Step-by-step explanation:

12=3(x-9)

divide both sides by three

4=x-9

add 9 to both sides

x=13

so, the x intercept is (13,0)

7 0
2 years ago
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Answer:

Explanation: start by adding 34 to both sides to make the variable stand alone giving you
7y is greater than or equal to 42
Then divide 7 into both sides to give you the answer of
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As division is the inverse of multiplication, the rules for division are the same as the rules for multiplication. So when multiplying and dividing positive and negative numbers remember this: If the signs are the same the answer is positive, if the signs are different the answer is negative.
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