<span>The vertices of are D(7, 3), E(4, -3), and F(10, -3)
Prove tat DE = DF
Length of a segment = </span>√[(x₂ - x₁) +(y₂ -y₁)]
DE = √([4-7)² + (-3 -3)²] = √45 = 3√5
DF = √[(10-7)² +(-3 -3)²] = √45 b= 3√5
Hence DE = DF = 3√5 and DEF is ISOSCELES
Answer:
the answer is 2: one pair of sides is parallel and the other pair is congruent.
Step-by-step explanation:
What do I need to solve :)
