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2 years ago

F(x)=x^2 what is g(x)

Mathematics

1 answer:

Svetradugi [14.3K]2 years ago

5 0

Answer:

Step-by-step explanation:

well, we just need to substitute the known point to each option.

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The word ___________________ means parts per hundred.

scZoUnD [109]

Answer:PHR

Step-by-step explanation:

PHR means parts per hundred defenition.

7 0

3 years ago

A consumer organization estimates that 35% of the households in a particular community have one television set, 39% have two set

nikitadnepr [17]

Answer:

90%

Step-by-step explanation:

Probability of households with one TV = 35% or 0.35

Probability of households with two sets = 39% or 0.39

Probability of households with three or more = 16% or 0.16

The probability of a household with no TV set = 0.10 or 10% (1 - 0.35 - 0.39 - 0.16)

Therefore, the probability of a household with at least one or more sets = 90% (35% + 39% + 16%) or 100% - 10%.

Probability is the chance that something may occur out of many events. To calculate probability, we divide the number of events by the number of possible outcomes.

5 0

2 years ago

Otra forma de representar 42/9

Oksi-84 [34.3K]

Answer:

(84/18, 14/3). These are the same as 42/9

3 0

2 years ago

What is 2+2 GUYS I REALLY NEED HELP MY KINDERGARDEN TEACHER IS COMING!!!!!

Ket [755]

Answer:

It's 5

Step-by-step explanation:

Good Luck

7 0

2 years ago

Read 3 more answers

Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the

VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

$\lim_{x \to 2} f(x) = 1$

$\lim_{x \to 2} g(x) = -4$

$\lim_{x \to 2} h(x) = 0$

a) Applying properties of limits

$\lim_{x \to 2} f(x) + 5g(x) = \lim_{x \to 2} f(x) + 5 \lim_{x \to 2} g(x) = 1 + 5*-4 = -19$

b) Applying properties of limits

$\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64$

c) Applying properties of limits

$\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1$

d) Applying properties of limits

$\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16$

e) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0$

f) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0$

3 0

3 years ago