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Amiraneli [1.4K]
3 years ago
11

A 3.42 kg mass hanging vertically from a spring on the Earth (where g = 9.8 m/s2) undergoes simple oscillatory motion. If the sp

ring constant is 12 N/m, find the period of oscillation of this setup on the moon, where g = 1.6 m/s2.
Physics
1 answer:
sineoko [7]3 years ago
3 0

Answer:

Time period of oscillation on moon will be equal to 3.347 sec

Explanation:

We have given mass which is attached to the spring m = 3.42 kg

Spring constant K = 12 N/m

We have to find the period of oscillation

Period of oscillation is equal to T=2\pi \sqrt{\frac{m}{K}}, here m is mass and K is spring constant

So period of oscillation T=2\times 3.14\times \sqrt{\frac{3.42}{12}}

T=2\times 3.14\times 0.533=3.347sec

So time period of oscillation will be equal to 3.347 sec

As it is a spring mass system and from the relation we can see that time period is independent of g

So time period will be same on earth and moon

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William James was a scientist who has established a laboratory in which Functionalism approach is used. Functionalism was not accepted in America. Functionalism was a reaction to structuralism. William James was not satisfied with structuralism and then he proposed Functionalist method. William James  suggested that psychology should be practical instead of theoretical as was proposed in the structuralist method. He also suggested that the existence of  consciousness and mind has a particular purpose, which should be the focus of the study.


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