A wood pipe having an inner diameter of 3 ft. is bound together using steel hoops having a cross sectional area of 0.2 in.2 The
allowable stress for the hoops is σallos=11.4 ksi. Determine the maximum spacing s along the pipe so that the pipe can resist an internal gauge pressure of 4 psi.
1 answer:
Answer:
31.67 in
Explanation:
Given:
Diameter of the pipe, D = 3ft = 36 in
cross-sectional area of the steel = 0.2 in²
Note: Refer to the figure attached
From the free body diagram represented in the figure, we have
ΣFx = 0
or
pressure × projected area = 2 × Force in steel
Now, the projected area = spacing (s) × diameter of the wood pipe
force in steel = stress in steel (σ) × cross-sectional area of the steel
on substituting the values we get
4 ksi × (s × 36 in) = 2 × σ × 0.2 in²
also, allowable hoop stress = 11.4 ksi
thus,
σ = 11.4 ksi = 11.4 × 10³ psi
therefore, we have
4 psi × (s × 36 in) = 2 × 11.4 × 10³ psi × 0.2 in²
thus,
s = 31.67 in
hence the maximum spacing is 31.67 in
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Answer:
Explanation:
Given:
time (t = 10.0 sec)
power = 150 Hp
We need to find the energy transformed by a 150 Hp engine in 10 s.
Solution:
First we convert 150 Hp in watt.
So, power (p = 111900 watt)
We know that, if we multiply power by time, we get energy transform by engine.
-----------(1)
Where:
P ⇒ power.
E ⇒ Energy.
t ⇒ time.
Substitute p = 111900 watt and t = 10 s in equation 1.
Therefore, a 150 Hp engine could transform 1,119,000 joules energy in 10 s.