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vivado [14]
2 years ago
11

To prevent dehydration when exercising on hot and humid days it is vital to:

Physics
2 answers:
Nostrana [21]2 years ago
8 0
Drink water before, during, and after your exercise activity! i would rlly appreciate brainliest:D
svet-max [94.6K]2 years ago
3 0

Answer:

Drink water before, during, and after your exercise activity.

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Assuming that the circuit is in the steady state, what is the total energy stored in the two capacitors? j
Neporo4naja [7]

<span>The total energy stored is the sum of the energy stored in the capacitors. If the capacitors  are series connected capacitors, then the charging current is the same for both capacitors. This means that each capacitor stores the same energy and the stored energy is two times the energy of any of the capacitors.</span>





8 0
3 years ago
1)
Ket [755]

Answer:

1) D

2) A

Explanation:

1) Each group has the same number of valence electrons, which are the outer electrons.

2) Ionic bonds are between a metal and non - metal, the metal being sodium and the non - metal being chlorine.

3 0
3 years ago
What is the average acceleration of the particle between 0 seconds and 4 seconds? A. 0 meters/second2 B. 0.04 meters/second2 C.
lisov135 [29]

Answer

D. 0.25 meters/second2

Explanation

The average acceleration is the ratio of change in velocity to the change in time of travel.Taking in this case that the change of velocity is a unit, then Average acceleration is given by;

Aacc=Vf-Vi/Tf-Ti

where Vf=final velocity,Vi=initial velocity' Tf=final time, Ti=initial time

Vf-Vi=1m/s

Tf-Ti=4-0=4seconds

Avacc=1/4=0.25m/s2

6 0
3 years ago
A particle of charge 2.0 x 10^-8C experiences an upward force of magnitude 4.0 x10^-6 when it is placed in a particular point in
koban [17]

Answer:

a) The electric field at that point is 2.0\times 10^{2} newtons per coulomb.

b) The electric force is 2.0\times 10^{-6} newtons.

Explanation:

a) Let suppose that electric field is uniform, then the following electric field can be applied:

E = \frac{F_{e}}{q} (1)

Where:

E - Electric field, measured in newtons per coulomb.

F_{e} - Electric force, measured in newtons.

q - Electric charge, measured in coulombs.

If we know that F_{e} = 4.0\times 10^{-6}\,N and q = 2.0\times 10^{-8}\,C, then the electric field at that point is:

E = \frac{4.0\times 10^{-6}\,N}{2.0\times 10^{-8}\,C}

E = 2.0\times 10^{2}\,\frac{N}{C}

The electric field at that point is 2.0\times 10^{2} newtons per coulomb.

b) If we know that E = 2.0\times 10^{2}\,\frac{N}{C} and q = 1.0\times 10^{-8}\,C, then the electric force is:

F_{e} = E\cdot q

F_{e} = \left(2.0\times 10^{2}\,\frac{N}{C} \right)\cdot (1.0\times 10^{-8}\,C)

F_{e} = 2.0\times 10^{-6}\,N

The electric force is 2.0\times 10^{-6} newtons.

7 0
3 years ago
Here is more points drip students - drip king
levacccp [35]
Answer
Thanks
Explanation
4 0
3 years ago
Read 2 more answers
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