Answer:
D
Step-by-step explanation:
P,Q, and R are point so vertices
Answer:

Step-by-step explanation:
we are given that A vegetable garden and a surrounding as a shaped like a square that together a 11 ft wide. The path is 2 feet wide.since together the width of Vegetable garden and path is 11 ft, the width of the vegetables garden will be the difference between the total width and the width of path Thus,

simplify substraction:

recall that, every single side of a square is equal to each other therefore the the area of the garden will be

simplify square:

together the garden and path makes a square of every side length 11 ft saying that the area will be:

simplify square:

the area of path will be the difference between the total area and the garden area therefore,

simplify addition:

to figure out how many bags are needed to cover the path. we just need to divide the area of the path by the area of a bag of gravel and that yields:

simplify division:

hence,
<u>4</u> bags are needed to cover the path.
Answer:
or 
Step-by-step explanation:
we know that
To find the unit rate divide 27 1/5 by 4/5
but first
Convert mixed number to an improper fraction

so

Answer:
no hablo ingles
Step-by-step explanation:
??y voy a 5c
<u>Given:</u>
Each circle has a diameter of 2 inches each.
The outer square has a side length of 4 inches and the square ABCD has a side length of 2 inches.
<u>To find:</u>
The area of the shaded region.
<u>Solution:</u>
Each circle has a diameter of 2 inches. The square ABCD is at the center of each circle so it has a side length of 1 inch.
To determine the area of the shaded region, we subtract the area of the quarter-circles in the square ABCD from the area of the square ABCD.
The area of a quarter-circle 
All the quarter-circles have a radius of 1 inch.
The area of 1 quarter-circle 
The area of 4 quarter-circles 
So the area of the quarter-circles in the square ABCD is 3.1514 square inches.
The area of a square 
The area of square ABCD 
The area of the shaded region 
The area of the shaded region is 0.8585 square inches.