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Ira Lisetskai [31]
3 years ago
11

Solve this problem : 2x- 3 (y-2x) + (-5) (-2y)

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
7 0
2x - 3(y - 2x) + (-5)(-2y)

Simplify everything.

2x - 3y + 6x + 10y

Add like terms.

(2x + 6x) + 10y

8x + 10y

~Hope I helped!~


liq [111]3 years ago
4 0
2x - 3(y - 2x) + (-5)(-2y)

you multiply -3(y - 2x) first and then (-5)(-2y)

2x - 3y + 6x + 10y 

Combine like terms

2x + 6x - 3y + 10y
8x + 7y


8x + 7y is your answer
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If integral 1 to 5 f(x)dx =36/15 what is the value of integral from 5 to 1 f(x)dx?<br><br><br>​
fredd [130]

Answer:

  -36/15

Step-by-step explanation:

If the indefinite integral of f(x)dx is F(x), then your integral from 1 to 5 is ...

  F(5) -F(1) = 36/15

The integral in the reverse direction is ...

  F(1) -F(5) = -(F(5) -F(1)) = -36/15

6 0
3 years ago
Find the area of the shape shown below. Please answer.
dimulka [17.4K]

Answer:

32

Step-by-step explanation:

2x2=4/2=2  small triangle, 2x2=4 small square, 6x2/2=6 med. triangle, 6+2+2=10x4=40/2=20

2+4+6+20=32

3 0
3 years ago
In a population of 10,000, there are 5000 nonsmokers, 2500 smokers of one pack or less per day, and 2500 smokers of more than on
Kazeer [188]

Answer:

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

Step-by-step explanation:

We have to write the transition matrix M for the population.

We have three states (nonsmokers, smokers of one pack and smokers of more than one pack), so we will have a 3x3 transition matrix.

We can write the transition matrix, in which the rows are the actual state and the columns are the future state.

- There is an 8% probability that a nonsmoker will begin smoking a pack or less per day, and a 2% probability that a nonsmoker will begin smoking more than a pack per day. <em>Then, the probability of staying in the same state is 90%.</em>

-  For smokers who smoke a pack or less per day, there is a 10% probability of quitting and a 10% probability of increasing to more than a pack per day. <em>Then, the probability of staying in the same state is 80%.</em>

- For smokers who smoke more than a pack per day, there is an 8% probability of quitting and a 10% probability of dropping to a pack or less per day. <em>Then, the probability of staying in the same state is 82%.</em>

<em />

The transition matrix becomes:

\begin{vmatrix} &NS&P1&PM\\NS&  0.90&0.08&0.02 \\  P1&0.10&0.80 &0.10 \\  PM& 0.08 &0.10&0.82 \end{vmatrix}

The actual state matrix is

\left[\begin{array}{ccc}5,000&2,500&2,500\end{array}\right]

We can calculate the next month state by multupling the actual state matrix and the transition matrix:

\left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4950&2650&2400\end{array}\right]

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

To calculate the the state for the second month, we us the state of the first of the month and multiply it one time by the transition matrix:

\left[\begin{array}{ccc}4950&2650&2400\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4912&2756&2332\end{array}\right]

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

If we repeat this multiplication 12 times from the actual state (or 10 times from the two-months state), we will get the state a year from now:

\left( \left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] \right)^{12} =\left[\begin{array}{ccc}4792.63&3005.44&2201.93\end{array}\right]

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

3 0
4 years ago
Which value of p makes the equation 18+ 2 (3p – 8) = –37 true?
Volgvan

Answer:

p = -6.5

Step-by-step explanation:

<u>Given:</u>

  • 18+ 2 (3p – 8) = –37

<u>Solving for p:</u>

  • 18+ 2 (3p – 8) = –37
  • 18 + 6p - 16 = -37
  • 6p + 2 = -37
  • 6p = -37 - 2
  • 6p = -39
  • p = -39/6
  • p = -6.5

Option 2 is correct in the list

3 0
3 years ago
What is the correct answer NEED IT ASAP PLEASE​
tia_tia [17]

It is the last choice

  • Amount she makes at McDonald's: 9x
  • Amount she makes at babysitting: 12x
  • Wants to save at least $1000

9x+12y\geq 1000

Hope that helps!

3 0
3 years ago
Read 2 more answers
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