3x^2-16x=x^2-30
-x^2 -x^2
2x^2-16x=-30
+30 +30
2x^2-16x+30=0
2x-6=0 or x-5=0
x=3 or x=5
A. 3,5
If you need an explanation, I can provide one. Hope it helped! If it didn't tell me what went wrong or what confused you.
Hi there, I don't know if I am right but I will try to solve this, 10x+24=64, subtract 24 from both sides, 10x+24-24=64-24=10x=40, divide both sides by 10, 10x/10=40/10, x=4
Answer:
equation;

Center (-4,2)
Radius is

Step-by-step explanation:
Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of

Where (h,k) is center
r is the radius
So first we group like Terms together

Add 7 to both sides


Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem

and

so we have



To find our center, h is -4 and k is 2
so the center is (-4,2)
The radius is

So the radius is 3 times sqr root of 3.
Answer:
8
Step-by-step explanation:
don't ask how I got it I looked it up
Explanation:
First, add by 25 both sides of an equation.

Then, simplify by equation and add/subtract by the numbers.

*The answer must be have a negative sign.

Hope this helps!
Thank you!
Have a great day!