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Musya8 [376]
3 years ago
13

Given: Elmwood St. and Oak Dr. are the same distance. All intersections are perpendicular.

Mathematics
1 answer:
vlabodo [156]3 years ago
8 0

Answer:

The above result is proved with the help of Pythagoras theorem and explained below.

Step-by-step explanation:

Given figure ABCD in which AD=BC and all angles intersect at right angle. Hence, the triangle formed inside ADC and ABC are right angled triangle.

In triangle ADC,

By applying Pythagoras theorem, we get

AC^{2}=AD^{2}+DC^{2}    →  (1)

In triangle ABC,

AC^{2}=AB^{2}+BC^{2}    →  (2)

Now, from eq (1) and (2)

Peach Tree Dr. is the same distance as Sycamore Ln.


AD^{2}+DC^{2} = AB^{2}+BC^{2}

⇒ DC^{2} = AB^{2}              (∵ AD=BC)

⇒ DC=AB                    (∵Distance can never negative)

Therefore, Peach Tree Dr. is the same distance as Sycamore Ln.


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