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Rama09 [41]
4 years ago
13

Is 7/8 or 11/10 closer to 1

Mathematics
1 answer:
Firlakuza [10]4 years ago
4 0
10. Find which one of the given fractions are value closer to 1. First = 7/8 Second = 11/10 Let’s start solving Let us start with the first value which is 7/8 => 7 needs to be divided with 8 => 7 / 8 = 0.875 Now, let’s solve the second value which is 11/10 => same with first solution., divide 11 by 10 => 11 / 10 => 1.1 Thus, 11/10 is the has the nearest value to 1.
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3 years ago
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

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We have to find whether the pipe is open,closed or open-closed or none.

Note:

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So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

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