Perform the indicated multiplication first: -15 + 5q + 4 = 5q - 11
Note that 5q appears on both sides of this equation. Cancelling, we get :
-11 = -11. This is always true. Thus, -5(3-q) +4=5q-11 is true for all q.
The derivative of 1/logx is With the chain rule.
1log(x)=log(x)−1 is ,= -1xlog(x)2 .
The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".
The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

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Answer:
25b?
Step-by-step explanation: