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Ivan
3 years ago
12

A chocolate company selects 1200 random packages to check their weight it finds that 30 packages have an incorrect weight. how m

any packages out of 6000 should the company predict have an incorrect weight.

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
5 0
150 packages

30/1200 = x/6000
6000/1200 = 5
30 x 5 = 150
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I REALLY NEED HELP PLEASE
Nezavi [6.7K]

Answer:

10

Step-by-step explanation:

given

\frac{s + ( - 7)}{ - 1}

we first need to simplify the expression before we find it's value when s=-3

positive times negative=negative

so the equation becomes

\frac{s - 7}{ - 1}

substituting s=-3 into the equation.

\frac{ - 3 - 7}{ - 1}

=

\frac{ - 10}{ - 1}

=the negatives cancel out leaving

= 10

7 0
3 years ago
At 2:00 p.m. two cars start toward each other from towns that are 240 miles apart. The rate of one car is 15 mph faster than the
Vesnalui [34]

Hello! :)

The <u>answer</u> is x+15!

~Hope it helps!~ :)

3 0
2 years ago
the equation y equals 0.25 x describes a proportional relationship between X and Y what is the constant of proportionality
Fittoniya [83]
The constant of proportionality is for every 1 x, there is 0.25 y. y = 0.25, and on a graph, x is always the "1." Since x is worth 1, y must be worth 0.25.
4 0
3 years ago
Emily, Carl and Antony altogether has 121 stamps. How many stamps doeas each of them have, if it is known, that Emily has 40% mo
Leviafan [203]

Answer:

Step-by-step explanation:

1. First, put together the information we have. Total = 121. Emily has 40% more than Carl, and Carl has 60% more than Antony.

2. Next, set each person as a variable. Antony = x. Carl = 1.6x. Emily = 1.4 times 1.6x.

3. Next, form an equation using these variables.

    x + 1.6x + (1.4 x 1.6x) = 121

    x + 1.6x + 2.24x = 121

    4.84x = 121

    x = 25

4. Finally, plug in x to our previous variables in step #2 to find the number of stamps Emily and Carl have.

<u>Antony</u>: x = 25 stamps

<u>Carl:</u> 1.6x = 40 stamps

<u>Emily</u>: 1.4 times 1.6x = 56 stamps

By the way, is this for RSM? If so, I am working on that problem right now and I searched up the solution but couldn't find it, so I stumbled upon this. I hope this helped!

8 0
3 years ago
Work out the length of the following rectangles
tiny-mole [99]

(a) a = 10.9 cm

(b) b = 20.78 cm

(c) c = 4.06 cm

<u>Explanation:</u>

(a)

height, h = 5cm

Hypotenuse, H = 12cm

Base, a = ?

Using pythagoras theorm:

(H)² = (h)² + (a)²

(12)² = (5)² + (a)²

119 = a²

a = 10.9 cm

(b)

Hypotenuse, H = 24 cm

Base, a = 12 cm

Height, b = ?

Using pythagoras theorm:

(H)² = (b)² + (a)²

(24)² = (b)² + (12)²

432 = b²

b = 20.78 cm

(c)

height, h = 4 cm

Hypotenuse, H = 5.7 cm

Base, c = ?

Using pythagoras theorm:

(H)² = (h)² + (c)²

(5.7)² = (4)² + (c)²

16.49 = c²

c = 4.06 cm

8 0
3 years ago
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