1/2 &50 0.5 hope this helps
Ok so first you will need 3 bags since 12*2 is 24 that wont be enough for the whole class so 12*3= 36 so now that we figured out how many bags we need now we have to multiply $8.00 by three the answer is $24
Answer:
<em>A.) There is a 3.4% chance that a random sample of 50 expectant mothers will have a mean age of 26.5 years old or greater if the mean age for a first time mother is 26 years old.</em>
Step-by-step explanation:
The mean age for a first time mother is assumed 26 years old (null hypothesis) and <em>p-value</em> of the sample mean (26.5 years ) is found as 0.034.
This is the probability of having first time mother mean age 26.5 or greater <em>under the assumption of null hypothesis. </em>
There are 210 different possible combinations
<h3>How to determine the number of possible combinations?</h3>
The given parameters are:
- Types of candy, n = 10
- Candies to taste, r = 6
The number of possible combinations is calculated using:
Combination = nCr
This gives
Combination = 10C6
Apply the combination formula
Combination = (10!)/((10 - 6)!6!)
Evaluate
Combination = 210
Hence, there are 210 different possible combinations
Read more about combination at:
brainly.com/question/11732255
Answer:
Step-by-step explanation:
you have t as a total amount of the whole class.
f= did not pass and you place the total number next to it like this; f/t represents that group. You continue this in your workings.
f/t = probability failed.
p/t = probability passed
c/t = probability completed
dc/t = probability did not complete
and draw a tree.
The random would be either of these, we know there s a possibility of 1/4 but the odds stay central. We look for a new way after this data is converted as a fraction and show these fractions as your answer.
