The sum of two consecutive even integers is 66. What is the value of three times the smaller number?
1 answer:
Answer: 96
Step-by-step explanation:
This problem can be written as x + y = 66.
Since the unknown integers are consecutive, y must equal x + 2 or x - 2. Let's rewrite the problem with this information.
66 = x + (x - 2) = 2x - 2
Solve for x.
x = 34
This means that the other integer is 34 - 2
Subtract.
34 - 2 = 32
The two integers are 32 and 34. We need to find the value of three times 32.
32 x 3 = 96
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