Answer:
AB= 0.625 units (3 s.f.)
∠BAC= 52.9° (1 d.p.)
∠ABC= 32.1° (1 d.p.)
Step-by-step explanation:
Please see the attached pictures for full solution.
- Find AB using cosine rule
- find ∠BAC using sine rule
- find ∠ABC using angle sum of triangle property
Answer:
Least is 7
Most is 12
Step-by-step explanation:
So 2 shirts for 12.
So 24
Take 24 off of both
Left with 21 to 36
21÷3 is 7
36÷3 is 12
Hope this helps
If we simplify like terms on left and right sides we gwt
16x + 9 = 4x
Its B
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
