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2 years ago

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on a gameboard spinner, martin won a prize on 4 spine and failed to win a prize on 6 other spins. Based on experimental probabil

ity, on how many of the next 20 spins should martin expect to win a prize?

1 answer:

PolarNik [594]2 years ago

3 0

Answer:

4 more

Step-by-step explanation:

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648 ÷ 8 tell how you solved pls i need help

stira [4]

Answer:

The answer is 81

Step-by-step explanation:

All you have to do is create your long division chart with 648 inside and 8 on the outside 8 can not go into 6 but it can go into 64 so 8 goes on top of 4 you subtract 64 minus 64 becayse 8 times 8 is 64. Lastly you bring down the other 8 and 8 goes into 8 once so you put 1 on top. And so thats how you get 81.

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2 years ago

Read 2 more answers

The probability of choosing a orange shirt is

Naya [18.7K]

The Tenth number percentage

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2 years ago

A calculator may be used for this question.

Lilit [14]

14 x 3/4 = 42/4 = 10.5 lbs
1 lb = 450 g...so 10.5 lbs = (10.5 x 450) = 4725 g.....1 g = 0.001 kg....so 4725 grams = (4725 x .001) = 4.725 kg

so ur gonna need a medium sized turkey.....4.725 kg...at 5.99 per kg =
(4.725 x 5.99) = $ 28.30 <==

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2 years ago

Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

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2 years ago

7.6 x 103^3 in standard form

Sever21 [200]

Answer:

8304725.2x

Step-by-step explanation:

Hope this helps. Plz give brainliest.

8 0

2 years ago