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icang [17]
3 years ago
14

Which graph can be used to find the solution for the equation 4x + 2 = x + 3? A) A B) B C) C D) D

Mathematics
2 answers:
Maurinko [17]3 years ago
6 0

Answer:

answer c

Step-by-step explanation:

Yea

larisa [96]3 years ago
4 0

Answer:

1/3

Step-by-step explanation:

4x+2=x+3

-2           -2

4x=x+1

-x        -x

3x=1

/3    /3

x=1/3

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What is the answer ?Pls help!
Nikolay [14]
It would also be 31.6
7 0
3 years ago
In the coordinate plane, what is the length of the line segment that connects points at (5,4) and (-3,-1)
baherus [9]

Answer:

9.434 units

Step-by-step explanation:

Given data

points (5,4) and (-3,-1)

x1= 5

y1= 4

x2= -3

y2= -1

The expression for the distance between two points is

d=√((x_2-x_1)²+(y_2-y_1)²)

substitute

d=√((-3-5)²+(-1-4)²)

d=√((-8)²+(-5)²)

d=√64+25

d=√89

d=9.4339

d= 9.434 units

Hence the distance between the points is 9.434 units

8 0
3 years ago
What’s is the answer to2(9)+7
AveGali [126]
The answer would be 25

9 times 2 is 18 plus 7 is 25
4 0
3 years ago
Read 2 more answers
Explain how a square is a recttangle​
maw [93]

Answer:

a square is a rectangle as it's a shape with 4 sides with 90degree angles, and pairs of sides are equal.

4 0
3 years ago
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Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)
Artemon [7]

Answer:

The coordinates of M are x = \frac{15}{2} and y = 1.

Step-by-step explanation:

Let be A = (-3,-6) and B = (12, 4) endpoints of segment AB and M a point located 7/10 the way from A to B. Vectorially, we get this formula:

\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}

\vec M - \vec A = \frac{7}{10}\cdot (\vec B - \vec A)

By Linear Algebra we get the location of M:

\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)

\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A

\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot  \vec B

If we know that \vec A = (-3,-6) and \vec B = (12, 4), then:

\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)

\vec M = \left(-\frac{9}{10},-\frac{9}{5}  \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)

\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5}   \right)

\vec M = \left(\frac{15}{2} ,1\right)

The coordinates of M are x = \frac{15}{2} and y = 1.

6 0
3 years ago
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