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ollegr [7]
3 years ago
9

Pls help me with this its the last question

Mathematics
1 answer:
andreev551 [17]3 years ago
3 0

Answer:

10y+5n+3/6 im not too sure but I think its correct

btw envision gives you a try again

You might be interested in
Otieno is k years old.He is 5 years older than kidole what will be their age fours to come​
EleoNora [17]

Answer:

Otieno's age in 4 years: k+4

Kidole's age in 4 years: k-1

Step-by-step explanation:

k = Otieno's age

k-5 = Kidole's age

Their ages will increase by 4 years when 4 years pass.

k+4 = Otieno's age in 4 years

k-5+4 = Kidole's age in 4 years

k-1 = Kidole's age in 4 years (after simplifying the expression)

I hope this helps!

6 0
3 years ago
Is side “a” considered a leg or the hypotenuse in this right triangle?
skelet666 [1.2K]

Answer:

A leg.

Step-by-step explanation:

The hypotenuse is always the side that is across from the corner. In this triangle, the hypotenuse is 14.

6 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP 5TH GRADE
natka813 [3]

Answer:

The answer would be B.

Step-by-step explanation:

Hope this helps.

5 0
3 years ago
I have no idea on how to does this... and neither did half of my class. Help?!?!
MA_775_DIABLO [31]
1. y=10+2x y=10+2(6) y=22
6 0
3 years ago
Since 2010, when 102390 Cases were reported, each year the number of new flu cases decrease to 85% of the prior year. Predict th
BaLLatris [955]

Answer:

20,158 cases

Step-by-step explanation:

Let t=0 represent year 2010.

We have been given that since 2010, when 102390 Cases were reported, each year the number of new flu cases decrease to 85% of the prior year.

Since the flu cases decrease to 85% of the prior year, so the flu cases for every next year will be 85% of last year and decay rate is 15%.

We can represent this information in an exponential decay function as:

F(t)=102,390(1-0.15)^t

F(t)=102,390(0.85)^t

To find number of cases in 2020, we will substitute t=10 in our decay function as:

F(10)=102,390(0.85)^{10}

F(10)=102,390(0.1968744043407227)

F(10)=20,157.970260446597\approx 20,158

Therefore, 20,158 cases  will be reported in 2020.

3 0
3 years ago
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