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4 years ago

Help me please!!❤️❤️

Mathematics

1 answer:

barxatty [35]4 years ago

8 0

Answer:

4(x^2)(y^0)

Step-by-step explanation:

or 4(x^2) either one should be correct

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Expand and simplify (x+6)(x−11)

KatRina [158]

Answer:

x^2 - 5x - 66

Step-by-step explanation:

1. Distrubute the x to the x and -11 so you will get x^2 - 11x

2. Distrubute the 6 to x and -11 and you get 6x - 66

3. Combine like terms (x^2 - 11x + 6x - 66) you will get x^2 - 5x - 66

7 0

2 years ago

Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The m

marshall27 [118]

Answer:

1. 0.0000454

2. 0.01034

3. 0.0821

4. 0.918

Step-by-step explanation:

Let X be the random variable denoting the number of passengers arriving in a minute. Since the mean arrival rate is given to be 10,

$X \sim Poi(\lambda = 10)$

1. Requires us to compute

$P(X = 0) = e^{-10} \frac{10^0}{0!} = 0.0000454$

2. We need to compute $P(X \leq 3) = P(X =0) + P(X =1) + P(X =2) + P(X =3)$

$P(X =1) = e^{-10} \frac{10^1}{1!} = 0.000454$

$P(X =2) = e^{-10} \frac{10^2}{2!} = 0.00227$

$P(X =3) = e^{-10} \frac{10^3}{3!} = 0.00757$

$P(X \leq 3) =0.0000454+ 0.000454 + 0.00227 + 0.00757 = 0.01034$

3. The expected no. of arrivals in a 15 second period is = $10 \times \frac{1}{4} = 2.5$ . So if Y be the random variable denoting number of passengers arriving in 15 seconds,

$Y \sim Poi(2.5)$

$P(Y=0) = e^{-2.5} \frac{2.5^0}{0!} = 0.0821$

4. Here we use the fact that Y can take values $0,1, \dotsc$ . So, the event that "Y is either 0 or $\geq$ 1" is a sure event ( i.e it has probability 1 ).

$P(Y=0) + P(Y \geq 1) = 1 \implies P(Y \geq 1) = 1 -P(Y=0) = 1 - 0.0821 = 0.918$

3 0

3 years ago

Can sum one help me

sleet_krkn [62]

Answer:

help with what exactly

8 0

3 years ago

Sam Long anticipates he will need approximately $227,300 in 14 years to cover his 3-year-old daughter's college bills for a 4-ye

SSSSS [86.1K]

Answer:

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Step-by-step explanation:

4 0

4 years ago

Please help ! no links please

vodka [1.7K]

All triangles must have angles that add up to the same amount of degrees, so if the two triangles share one exact point, it is assumed that those angles would be the same. Basically just use the fact that the sides are the same and marked by dashes, and the missing line can be proven with the use of the angles that are in between the point that both share.

5 0

3 years ago