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4 years ago

Help me please!!❤️❤️

Mathematics

1 answer:

barxatty [35]4 years ago

8 0

Answer:

4(x^2)(y^0)

Step-by-step explanation:

or 4(x^2) either one should be correct

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(DESPERATE PLEASE HURRY)<br> question down below<br> please show the work

const2013 [10]

Answer:

-46 again....

Step-by-step explanation:

4 0

3 years ago

Donna rents a car. she has a fixed rate of $105.00 weekly, $12.00 per week for insurance, and she spends $15.50 weekly on gas. w

nikdorinn [45]

The answer to this problem is 528

6 0

3 years ago

Find the solutions of <img src="https://tex.z-dn.net/?f=y%3Dx%5E%7B2%7D%2B2" id="TexFormula1" title="y=x^{2}+2" alt="y=x^{2}+2"

Eva8 [605]

Answer:

x is $\frac{1\ + \sqrt{3} i}{2}$ AND

$\frac{1\ - \sqrt{3} i}{2}$

y = $\frac{3\ + \sqrt{3} i}{2}$ And

$\frac{3\ - \sqrt{3} i}{2}$

Step-by-step explanation:

Given two equations are :

y = x² + 2 And

y = x + 1

So, the equation can be written as

x² + 2 = x + 1

Or, x² - x + ( 2 - 1) = 0

Or, x² - x + 1 = 0

This is in the form of quadratic equation

So, Roots of equation x be :

x = $\frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, x = $\frac{1\pm \sqrt{-1^{2}-4\times 1\times 1}}{2\times 1}$

Or , x = $\frac{1\pm \sqrt{-3}}{2}$

Hence the two value of x is $\frac{1\ + \sqrt{3} i}{2}$ AND

$\frac{1\ - \sqrt{3} i}{2}$

So , y = $\frac{3\ + \sqrt{3} i}{2}$ And

$\frac{3\ - \sqrt{3} i}{2}$

5 0

3 years ago

Y=-x+1<br> -2x-y=2 substitution

UNO [17]

Step-by-step explanation:

$y=-x+1 \\ -2x-y=2$ given

$- 2x-( - x + 1)=2 \\ - 2x + x - 1 = 2 \\ - x = 2 + 1 \\ - x = 3 \\ x = 3$

put x

$-2( - 3)-y=2 \\ 6 - y = 2 \\ - y = 2 - 6 \\ - y = - 4 \\ y = 4$

8 0

3 years ago

Use the distributive property to remove the parenthese:<br> (-2+5u+v) (-8)

aleksandrvk [35]

Answer:

16 - 40u - 8v

Step-by-step explanation:

(- 2 + 5u + v)(- 8) ← multiply each term in the parenthesis by - 8

= 16 - 40u - 8v

3 0

3 years ago