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Valentin [98]
3 years ago
5

Help me please!!❤️❤️

Mathematics
1 answer:
barxatty [35]3 years ago
8 0

Answer:

4(x^2)(y^0)

Step-by-step explanation:

or 4(x^2) either one should be correct

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Read 2 more answers
F(x) = x2+3x+2 x2+5x+4 Why is there no zero at x = –1?
dmitriy555 [2]
You could rewrite F(x) as

\dfrac{x^2+3x+2}{x^2+5x+4}=\dfrac{(x+1)(x+2)}{(x+1)(x+4)}

and be tempted to cancel out the factors of x+1. But this cancellation is only valid when x\neq-1.

When x=-1, you end up with the indeterminate form \dfrac00, which is why -1 is not a zero.
7 0
3 years ago
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