Dane started running at half past three in the afternoon. He stopped running at ten minutes after four. How long did Dane run?
2 answers:
You might be interested in
<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
Hey there :)
When you take x⁴ from the denominator to the numerator, you get x⁻⁴
Therefore, first option:
is one correct expression
When you exchange the numerator and denominator, you will have negative powers on them. Such as when you take 6 to the numerator you will have 6⁻¹ and 5 to the denominator is 5⁻¹
So, second option :
is another right expression.
When you take x⁴ from the denominator to the numerator, you get x⁻⁴
Therefore, first option:
When you exchange the numerator and denominator, you will have negative powers on them. Such as when you take 6 to the numerator you will have 6⁻¹ and 5 to the denominator is 5⁻¹
So, second option :