m∠BAC = 27°
Solution:
ABCD is a quadrilateral.
AB and CD are parallel lines.
Given m∠BCD = 54°
AC bisect ∠BCD.
m∠DCA + m∠CAB = m∠BCD
m∠DCA + m∠DCA = 54° (since ∠ACB = ∠DCA)
2 m∠DCA = 54°
Divide by 2 on both sides, we get
m∠DCA = 27°
AB and CD are parallel lines and AC is the transversal.
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠BAC = m∠DCA
m∠BAC = 27°
Hence m∠BAC = 27°.
F(x) = -x + 4
Substitute x = -2 to the equation:
f(-2) = -(-2) + 4 = 2 + 4 = 6
Answer: A) 6
Answer:
there isn't any choices but 6/12+1/12=7/12
or 4/12+3/12=7/12
hope this helps
have a good day :)
Step-by-step explanation:
5 and 4 are two in inequalities because they make 5 bigger then 13
[tex}r - 5 \frac{5}6 + 5\frac{5}6 = 10 +5\frac{5}6{/tex]
