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4 years ago

Coefficient of 8x+7y

Mathematics

2 answers:

Nina [5.8K]4 years ago

7 0

Answer: I’m pretty sure it is 8 and 7 because those are the numbers multiplied with variables.

bulgar [2K]4 years ago

5 0

Answer:

Step-by-step explanation:

Identify the exponents on the variables in each term, and add them together to find the degree of each term.

8x→1

7y→1

The largest exponent is the degree of the polynomial.

The leading term in a polynomial is the term with the highest degree.

The leading coefficient of a polynomial is the coefficient of the leading term.

____________________________________________________________

The leading term in a polynomial is the term with the highest degree.

The leading coefficient in a polynomial is the coefficient of the leading term.

List the results.

Polynomial Degree: 1

Leading Term: 8x

Leading Coefficient: 8

Hope This Helps!!!

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lyudmila [28]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Side BC

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

$\therefore \tt \boxed{ \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} = { \bigg(\frac{BC}{EF} \bigg)}^{2} }$

❍ Putting the values, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

$\implies \tt \dfrac{64 \: {cm}^{2} }{12 \: {cm}^{2} } = { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}$

❍ By solving we get,

$\implies \tt \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }} = \bigg( \dfrac{BC}{15.4 \: cm} \bigg)$

$\implies \tt \sqrt{\dfrac{{(8 \: cm)}^{2} }{ {(11 \: cm)}^{2} }} = \bigg( \dfrac{BC}{15.4 \: cm} \bigg)$

$\implies \tt \dfrac{8 \: cm}{11 \: cm} = \dfrac{BC}{15.4 \: cm}$

$\implies \tt \dfrac{8 \: cm \times 15.4 \: cm}{11 \: cm} = BC$

$\implies \tt \dfrac{123.2 }{11 } cm = BC$

$\implies \tt \purple{ 11.2 \: cm} = BC$

Hence, BC = 11.2 cm.

${\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}$

★ Figure in attachment.

$\rule{280pt}{2pt}$

4 0

3 years ago

NEED HELP ASAP!!! TYSM IF YOU HELP ME

VMariaS [17]

Answer:

10.44

Step-by-step explanation:

it Says to use the biggest number on ther which was 15.50

soyou had to subtract 40% off 15.50 then add 8% which was the tax

stay safe wear your mask and don’t be a Karen jk but still wear your mask and saty safe :)

mark brainliest if correct

7 0

3 years ago

Identify the interval(s) on which the function y = -x2 + 5x + 14 is positive.

mihalych1998 [28]

Given:

$y=-x^2+5x+14$

To find:

The interval on which the given function is positive.

Solution:

We have,

$y=-x^2+5x+14$

Splitting the middle term, we get

$y=-x^2+7x-2x+14$

$y=-x(x-7)-2(x-7)$

$y=(x-7)(-x-2)$

$y=-(x-7)(x+2)$

Using zero product property, we get

$x-7=0\text{ and }x+2=0$

$x=7\text{ and }x=-2$

-2 and 7 divide the number line is three interval.

Interval Signs of $y=-(x-7)(x+2)$ Result

(-∞,-2) (-)(-)(-) Negative

(-2,7) (-)(-)(+) Positive

(7,∞) (-)(+)(+) Negative

So, the function is positive for the interval (-2,7), i.e., -2 < x < 7.

Therefore, the correct option is D.

7 0

3 years ago

Which is correct regarding the statement: “If x is an odd integer, then the median of x , x + 2, x + 6, and x + 10 is an odd num

Nookie1986 [14]

Lets find out...lets make x = 3

x = 3
x + 2 = 3 + 2 = 5
x + 6 = 3 + 6 = 9
x + 10 = 3 + 10 = 13

so we have : 3,5,9,13....median would be (5 + 9) / 2 = 14/2 = 7
so that is a correct statement.

8 0

3 years ago

How many solutions are in -2x+3 = -2x+3

lys-0071 [83]

Answer:

Infinite Solutions

Step-by-step explanation:

If the two equations are the same (as they are here), the amount of solutions would be infinite. I hope this helps!

5 0

3 years ago