Answer
a) y | p(y)
25 | 0.8
100 | 0.15
300 | 0.05
E(y) = ∑ y . p(y)
E(y) = 25 × 0.8 + 100 × 0.15 + 300 × 0.05
E(y) = 50
average class size equal to E(y) = 50
b) y | p(y)
25 | 
100 | 
300 | 
E(y) = ∑ y . p(y)
E(y) = 25 × 0.4 + 100 × 0.3 + 300 × 0.3
E(y) = 130
average class size equal to E(y) = 130
c) Average Student in the class in a school = 50
Average student at the school has student = 130
We have that the value of x in the diagram at the right is
x=109
From the question we are told
Use this idea to find the value of x in the diagram at right.
From The diagram we have a Triangle with its base angles equal
Generally the equation for the Triangle is mathematically given as
180=2b+y
Where
b=Base angles
Since Angle on a straight line is 90
Therefore
180=71+x
x=109
In conclusion
The value of x in the diagram at the right is
x=109
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4/2 for the first one
14/2 for the second one
Simplified it would be
2/1 for the first
7/1 for the second
12+6x was subtracted from the left but only 12 was subtracted from the right.
6x and 6 are not equal unless x=1
X=-11/15
Answer:
140 ml
Step-by-step explanation:
60/3 = 20
20x7 = 140
