Evaluate 3 + 6 x 4

Is this circumference or Area ? <br> Plz help me plz I beg u no links olz

Yuliya22 [10]

Answer:

This would be area because you are trying to find the total <u>area</u> that the sprinkler water touched and not the perimeter(circumference) of it

Hope this helps :)

7 0

3 years ago

I need help with this

Debora [2.8K]

C because if you look at the intercept it’s a y and the y inception is equivalent to 4 so y=4x-14

5 0

3 years ago

Which methods could you use to calculate the y-coordinate of the midpointof a vertical line segment with endpoints at (0,0) and

vodka [1.7K]

Answer:

y-coordinate of midpoint of line segment joining the endpoints (0,0) and (0,15) is 7.5

Step-by-step explanation:

Given two end points of line segment that are (0,0) and (0,15). If we have to find the y-coordinate of midpoint of a vertical line segment then we apply mid point formula.

The Midpoint formula is used when one is need to find the exact center point between two given points.

The mid point M of line segment $A(x_{1},y_{1})$ and $B(x_{2},y_{2})$ can be calculated as

$M(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

Mid point of line joining the end points (0,0) and (0,15) is

$M(\frac{0+0}{2},\frac{0+15}{2})$ =M(0,7.5)

Hence, y-coordinate of midpoint of line segment joining the endpoints (0,0) and (0,15) is 7.5

6 0

4 years ago

1. The beginning steps for determining the center and radius of a circle using the completing the square method are shown below:

svet-max [94.6K]

(1) Answer : $(x^2 - 6x + 9) + (y^2- 4y + 4) = 3 + (9 + 4)$

Step 1: $x^2 - 6x + y^2 - 4y = 3$

Step 2: $(x^2- 6x) + (y^2 - 4y) = 3$

In completing the square method we take coefficient of x and divide by 2 and the square it . Then add it on both sides

The coefficient of x is -6. $\frac{-6}{2}$ = (-3)^2 = 9

The coefficient of y is -4. $\frac{-4}{2}$ = (-2)^2 = 4

Step : $(x^2- 6x + 9) + (y^2 - 4y + 4) = 3 +9 + 4$

(2) $x^2 + y^2 + 6x - 6y + 2 = 0$

To find center and radius we write the equation in the form of

$(x-h)^2 + (y-k)^2 = r^2$ using completing the square form

Where (h,k) is the center and 'r' is the radius

$x^2 + y^2 + 6x - 6y + 2 = 0$

$(x^2 + 6x) + (y^2 - 6y) + 2 = 0$

In completing the square method we take coefficient of x and divide by 2 and the square it . Then add it on both sides

$(x^2 + 6x + 9) + (y^2 - 6y + 9) = -2 + 9 + 9$

$(x + 3)^2 + (x - 3)^2 = 16$

Here h= -3 and k=3 and $r^2 = 16$ so r= 4

Center is (-3,3) and radius = 4

(c) Step 1: $x^2 + 8x + y^2 - 6y = 11$

Step 2: $(x^2 + 8x) + (y^2 - 6y) = 11$

Step 3: $(x^2 + 8x + 16) + (y^2 - 6y + 9) = 11 + (16 + 9)$

Step 4: $(x^2 + 8x + 16) + (y^2 - 6y + 9) = 36$

We factor out each quadratic

(x^2 + 8x + 16) = (x+4)(x+4) = $(x+4)^2$

((y^2 - 6y + 9)) = (x-3)(x-3) = $(x-3)^2$

Step 5 : $(x + 4)^2 + (y - 3)^2 = 6^2$

5 0

3 years ago

B= [2 8 .6 3 ] A= 3 0 2 -1]<br> what is BA ?

Genrish500 [490]

The dot product of two vectors is defined as the sum of the multiplication of each of its components.
We have then:
B = [2 8 .6 3]
A = [3 0 2 -1]
Making the product point:
BA = [2 8 .6 3] [3 0 2 -1]
BA = (2 * 3) + (8 * 0) + (0.6 * 2) + (3 * (- 1))
BA = 4.2
Answer
BA = 4.2

5 0

3 years ago

Evaluate 3 + 6 x 4 - 16/2