Answer:The goal of transcription is to make a RNA copy of a gene's DNA sequence. For a protein-coding gene, the RNA copy, or transcript, carries the information needed to build a polypeptide (protein or protein subunit). Eukaryotic transcripts need to go through some processing steps before translation into proteins.
Explanation:
When a BB male and a Bb female are crossed, 50% BB and 50% Bb genotypes are produced and a 100% black phenotype.
The entire number of genes that an organism receives from its parents makes up its genotype. Alleles, which are pairs of these genes, are found. One gene is dominant and one gene is recessive in each allele.
The dominant gene is always expressed in a cross if it is present. Only when a pair of alleles is made up of two recessive genes does the recessive gene express itself. In this instance, the white fur is subordinate to the black fur. White fur is represented as b, while black fur is represented as B.
We can see that when we cross the BB male and Bb female, we will get a genotype that is 50% BB and 50% Bb, as well as a phenotype that is 100% black fur.
Parents: BB x Bb
Gametes: B, B, and B, b
Offspring: BB, BB, Bb, Bb
The genotypic ratio = 1:1
The phenotypic ratio = 1:0
Genotype probabilities:
P(BB) = 2/4 = 0.5 or 50%
P(Bb) = 2/4 = 0.5 or 50%
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Answer: 48.93 mL of sprite
Volume of blood in 7 Kg human = 5 L
Percentage of plasma in blood = 55%
Volume of plasma in 5 L blood = (1 L = 10 dL)
Concentration of glucose in plasma = 80 mg/dL
Amount of glucose present in 27.5 dL : 80 mg /dL × 27.5 dL= 2200 mg
Let the volume of sprite with 2200 mg glucose be x
Concentration of glucose in sprite = 44.96 mg/mL
Explanation:
Answer:
Explanation:
attempted to control their population growth
