Answer:A≈314.16in²
Step-by-step explanation:
Unit Conversion:
d=20in
Using the formulas
A=πr2
d=2r
Solving forA
A=1
4πd2=1
4·π·202≈314.15927in²
Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
Answer:
Shane started the problem correctly
Step-by-step explanation:
We are given problem (-5) - (-1 3/4).
Mariah started the problem as (-5) + 1 - 3/4
Shane started the problem as (-5) + 1 + 3/4
We need to find who started the problem correctly.
The problem should be started by converting the mixed fraction into improper fraction i,e

Now we will solve bracket by multiplying -1 with term inside the bracket i.e


Let's compare both the procedures now:
Mariah:



Therefore, Mariah did not start the problem correctly.
Shane:



Therefore, Shane started the problem correctly.
Answer:
4.32
Step-by-step explanation:
You can multiply 16 by 0.27 to get the answer.
16*0.27=4.32
You can check your work with estimation because 27% is about 1/4 of the number, and just by looking at the number, 4 is 1/4 of the number.
Let's call the younger student's age A and the older student's age B. The teacher's age will be T.
B = 2A
T = 5B
T+5 = 5(A+5)
Simplify the last equation.
T+5 = 5A+25
T = 5A+20
Now we have two equations solved for T, so we can set them equal to each other.
5B = 5A + 20
We can plug 2A in for B
5(2A) = 5A + 20
10A = 5A + 20
5A = 20
A = 4
To find T, we plug 4 in for A in T = 5A + 20
T = 5(4) + 20
T = 40
The answer is 40 years old.