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3 years ago

Whats 70-3x6+9 I need the answer plz

Mathematics

1 answer:

kumpel [21]3 years ago

7 0

70-3·6+9

Remember PEMDAS.

You must multiply the 3 and 6 together, and you would get 18.

Then, you subtract 18 from 70, which would give you 52.

And finally, you would add 9 to 52, getting 61 as your final answer.

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A right circular cone of radius 6 inches, side length of 16 inches and height of h inches. Which is closest to the height of a c

Elis [28]

Answer:

Height of cone (h) = 14.8 in (Approx)

Step-by-step explanation:

Given:

Radius of cone (r) = 6 in

Slant height (l) = 16 in

Find:

Height of cone (h) = ?

Computation:

Height of cone (h) = √ l² - r²

Height of cone (h) = √ 16² - 6²

Height of cone (h) = √ 256 - 36

Height of cone (h) = √220

Height of cone (h) = 14.832

Height of cone (h) = 14.8 in (Approx)

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3 years ago

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olasank [31]

Answer:

Output will be n+4 because :

when input is 1 output is 1+4=5

when input is 4 output is 4+4=8

when input is 5 output is 5+4 =9

so, when input is n output will be n+4

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2 years ago

What type of function is shown in the data in the table below?

Pavlova-9 [17]

The functions shows in the data table is an exponential function.

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2 years ago

Larry says 5×900 is less than 5×9000 is greater than 9000

Ne4ueva [31]

Answer:

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3 years ago

Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).

Step2247 [10]

Answer:

An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

Step-by-step explanation:

Given the points

(-4,1)

(4,3)

Finding the slope between the points (-4,1) and (4,3)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)$

$m=\frac{3-1}{4-\left(-4\right)}$

Refine

$m=\frac{1}{4}$

Point slope form:

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

in our case,

m = 1/4

(x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

$y-y_1=m\left(x-x_1\right)$

$y-1=\frac{1}{4}\left(x-\left(-4\right)\right)$

$y-1=\frac{1}{4}\left(x+4\right)$

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

5 0

3 years ago