Answer: The point estimate for the mean weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample 
= 31.2 pounds .
Step-by-step explanation:
The weights of spawning Chinook salmon in the Columbia river are normally distributed.
Given : The mean weight from your sample is 31.2 pounds with a standard deviation of 4.4 pounds.
The point estimate for the mean 
weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample i.e. is 31.2 pounds because the best point estimate for population mean is the sample mean. [in normal distribution]
Answer: 38/9
Step-by-step explanation: Because the fractions presented already have common denominators, the only thing you need to do in order to solve the problem is add the numerators. 36+2= 38, and you keep your denominator the same when adding fractions (when they are the same).
Answer: The cake density is 0.454 ounce per cubic inch and the fair price is $0.20 per ounce. What should be a fair price for each cake?
Step-by-step explanation:The cake density is 0.454 ounce per cubic inch and the fair price is $0.20 per ounce. What should be a fair price for each cake?
<span>Two or more decimal numbers are said to be equivalent decimals, when they name the same value (or same amount).
For example, the decimals: 0.2 = 0.20 = 0.200 = 0.2000 etc.
Thus by successive addition of zeros after the decimal part of the number after the decimal point means the same number and hence are equivalent.
Therefore, the decimals: 5.3, 5.30, 5.300, 5.3000 etc are all equivalent.</span>
Part 1) <span>Find the area
we know that
the area of the triangle is
A=b*h/2
in this problem
b=9
h=12
so
A=9*12/2-----> A=54 units</span>²
the answer part 1) isArea=54 units²Part 2) <span>Find the area of the kite
see the picture attached with letters to better understand the problem
we know that
The area of a Kite is </span><span>half the product of the diagonals
</span><span>
step 1
find CB
applying Pythagoras Theorem
AB</span>²=AC²+BC²------> BC²=AB²-AC²-----> BC²=5²-3²----> BC²=16
<span>BC=4
so
the diagonals are
(10+4) and (3+3)---------> 14 and 6
Area=(1/2)*[14*6]----> Area=42 units</span>²<span>
the answer Part 2) isthe area of a kite is 42 units</span>
²
