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Jlenok [28]
3 years ago
9

PLZ HELP IF YOU CAN PLZ ANSWER ALL 1. Quan plans to spend less than $80 for buying groceries. He plans to spend $68.25 on food a

nd spend the rest on juice. Each juice carton costs $3. He is curious how many juice cartons he can purchase before he runs out of money.
2. (a) Use x to represent the number of juice cartons Quan can purchase and write an inequality that can be used to solve for x.
Mathematics
2 answers:
DiKsa [7]3 years ago
4 0
Y=3X+68.25

80=3X+68.25
Subtract 68.25 from both sides
11.75=3X

Divide

11.75/3=3.91
He can't buy a portion of a juice but he doesn't have enough to buy 4

So he can afford 3 juice cartons
FinnZ [79.3K]3 years ago
3 0
$80.00-$68.25=$11.75
x=?
j=$3
$11.75/$3.00=x
x=3.9 (0.9 is not one so you can have 3 cartons)
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Please answer this and show your work please I really need help !!!
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Unless you just want to give money to the ice cream truck, for 0 items, you will pay 0.

Since the price of each item is $0.77, for one item you will pay $0.77. (Is that a surprise?)

Then for two items, you will pay $0.77 for each one, or $0.77 + 0.77 = $1.54. You can also compute this by making use of the fact that multiplication is a shortcut for repeated addition. The price can be found by $0.77×2 = $1.54 = f(2).

Similarly, for 3 items, you can add $0.77 three times: $0.77 + 0.77 + 0.77 = f(3), or you can use multiplication: $0.77×3 = $2.31 = f(3).

a) Our table looks like
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  (0, 0)
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b) By now, I'm sure you have realized that to find the price of x items, you multiply 0.77 by x.
  f(x) = 0.77x
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