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Xelga [282]
3 years ago
13

Help please..................

Mathematics
1 answer:
Ivahew [28]3 years ago
8 0
(f+g)(x) = f(x) + g(x)
(f+g)(x) = [ f(x) ] + [ g(x) ]
(f+g)(x) = [ 3x-2 ] + [ 2x+1 ]
(f+g)(x) = (3x+2x) + (-2+1)
(f+g)(x) = 5x - 1

Answer is choice B
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A researcher wishes to examine the relationship between years of schooling completed and the number of pregnancies in young wome
Ber [7]

Answer:

1. When amount of schooling increases by one year, the number of pregnancies will decrease by 4.

Step-by-step explanation:

Regression analysis is a statistical technique which is used for forecasting. It determines the relationship between two variables. It determines the relationship of two or more dependent and independent variables. It is widely used in stats to find trend in the data. It helps to predict the values of dependent and independent variables. In the given question, there is regression equation given. X and Y are considered as dependent variables. When number of schooling increases by 1 year then number of pregnancies will decrease by 4

5 0
2 years ago
Write the equation for a line that passes through the point (-3, 5) and is parallel to
gtnhenbr [62]

Answer:

y=3x+14

Step-by-step explanation:

We can use point-slope formula to find the equation.

y-5=3(x+3)

y-5=3x+9

y=3x+14

5 0
2 years ago
Read 2 more answers
-36 times a number minus 75 is equal to 65 less than the number. What is the number?
nadezda [96]
<span><span><span>−<span>36n</span></span>−75</span>=<span>n−65</span></span><span>−36n−75−n</span><span>=</span><span>n−65−n</span>
<span><span><span>−<span>37n</span></span>−75</span>=<span>−65</span></span><span><span><span><span>−<span>37n</span></span>−75</span>+75</span>=<span><span>−65</span>+75</span></span><span><span>−<span>37n</span></span>=10</span><span><span><span>−<span>37n</span></span><span>−37</span></span>=<span>10<span>−37

</span></span></span><span>n= <span><span>−10/</span>37  <--------- answer</span></span>
8 0
3 years ago
1. D=5.9 ft.
Shtirlitz [24]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Here's the solution ~

As we know, we can calculate the circumference of a circle in terms of its diameter as :

\qquad \sf  \dashrightarrow \:c =  \pi d

where, c = circumference and d = diameter

And also, circumference of circle is terms of radius (r) is :

\qquad \sf  \dashrightarrow \:c =  2\pi r

Now, let's move on to questions ~

<h3>First </h3>

\qquad \sf  \dashrightarrow \:3.14 \times 5.9

\qquad \sf  \dashrightarrow \: \approx18.53 \: ft

<h3 />

・ .━━━━━━━†━━━━━━━━━.・

<h3>Second</h3><h3 /><h3 /><h3 /><h3>\qquad \sf  \dashrightarrow \:3.14 \times 3.2</h3>

\qquad \sf  \dashrightarrow \: \approx10.048 \: ft

・ .━━━━━━━†━━━━━━━━━.・

<h3>Third</h3>

\qquad \sf  \dashrightarrow \:3.14 \times 6.1

\qquad \sf  \dashrightarrow \: \approx19.15 \: ft

・ .━━━━━━━†━━━━━━━━━.・

<h3>Fourth</h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  3.7

\qquad \sf  \dashrightarrow \: \approx2×11.62  \: m

\qquad \sf  \dashrightarrow \: \approx23.24  \: m

・ .━━━━━━━†━━━━━━━━━.・

<h3>Fifth </h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  6.2

\qquad \sf  \dashrightarrow \: \approx2× 19.47 \: units

\qquad \sf  \dashrightarrow \: \approx38.94  \: m

・ .━━━━━━━†━━━━━━━━━.・

<h3>Sixth</h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  5.1

\qquad \sf  \dashrightarrow \: \approx2×16.01 \: ft

\qquad \sf  \dashrightarrow \: \approx \: 32.02m

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt31" id="TexFormula1" title="\sqrt31" alt="\sqrt31" align="absmiddle" class="latex-formu
andreyandreev [35.5K]

Answer:

Decimal: 5.567764)

Step-by-step explanation:

Decimal: 5.567764)

3 0
2 years ago
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